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Irina18 [472]
3 years ago
15

An investment firm offers three types of equity investments,

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
8 0

Answer:

7.1

Step-by-step explanation:

A, B, and C. Of the firm's clients, 30% invest in A, 50% invest in B, and 20% invest in C. The rates of return are 10%, 6%, and 7% for A, B, and C, respectively. 7.1 plato

Fudgin [204]3 years ago
5 0

Answer:

<u>The expected value of the total return rate for the firm's clients is C. 7.4%</u>

Step-by-step explanation:

1. Let's review all the information given for solving the question:

Type of equity investments = A, B and C

Percentage of investment in each type of equity = 30% in A, 50% in B and 20% in C.

Rates of return of each type of equity investment = 10% for A, 6% for B and 7% for C.

2. Let's find the expected value of the total return rate for the investment firm:

Return rate for each type of investment = Percentage of investment * Rate of return

For A = 30% * 10% = 0.3 * 0.1  = 0.03

For B = 50% * 6% = 0.5 * 0.06 = 0.03

For C = 20% * 7% = 0.2 * 0.07 = 0.014

Total return rate = Return rate for A + Return rate for B + Return rate for C

Total return rate = 0.03 + 0.03 + 0.014 = 0.074

<u>Total return rate = 0.074 * 100 = 7.4%</u>

<u>The expected value of the total return rate for the firm's clients is C. 7.4%</u>

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The University of Central Florida's cheerleading team has eighteen males and twenty-one females. If h represents the height of a
Anuta_ua [19.1K]

Answer:

The range of heights of the cheerleaders is the interval [58, 74)

All real numbers greater than or equal to 58 inches and less than 74 inches

Step-by-step explanation:

we have

260 \leq 4h+28

Divide the compound inequality into two inequalities

260 \leq 4h+28 -----> inequality A

4h+28 -----> inequality B

Solve inequality A

260 \leq 4h+28

Subtract 28 both sides

232 \leq 4h

Divide by 4 both sides

58 \leq h

Rewrite

h \geq 58\ in

Solve the inequality B

4h+28

Subtract 28 both sides

4h

Divide by 4 both sides

h

therefore

The range of heights of the cheerleaders is the interval [58, 74)

All real numbers greater than or equal to 58 inches and less than 74 inches

3 0
3 years ago
Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio, si avanza medio kilómetro en bus y lo demás a pie ¿
Murljashka [212]

Answer:

Al estudiante le falta caminar \frac{1}{3} de kilómetro.

Step-by-step explanation:

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio. Dos tercios equivale a la fracción \frac{2}{3} .

El estudiante avanza medio kilómetro en bus. Un medio equivale a la fracción \frac{1}{2}, por lo tanto un medio es la mitad de una cantidad.  Para calcular la distancia recorrida en bus se realiza la siguiente multiplicación:

\frac{1}{2} *\frac{2}{3}

Resolviendo:

\frac{1}{2} *\frac{2}{3} =\frac{1*2}{2*3} =\frac{2}{6} =\frac{1}{3}

Entonces, la distancia recorrida en bus es \frac{1}{3} de kilómetro.

Para calcular la distancia recorrida a pie se calcula la diferencia entre la distancia total a recorrer por el estudiante y la distancia recorrida en bus. Esto es:

\frac{2}{3} - \frac{1}{3}

Resolviendo:

\frac{2}{3} - \frac{1}{3}=\frac{2-1}{3} =\frac{1}{3}

<u><em>Al estudiante le falta caminar </em></u>\frac{1}{3}<u><em> de kilómetro.</em></u>

6 0
3 years ago
PLEASE HELP!!!!!!!!!!
agasfer [191]

Answer:

a = 30

b = 15

c = 3

d = 30

e = 10

f = 20

Step-by-step explanation:

60 deg and a + 30 are alt int <S and congruent

a + 30 = 60

a = 30

a + 30 and a + 2b are corresponding angles and congruent

a + 2b = a + 30

2b = 30

b = 15

a + 2b and 5b - 5c are vertical angles and congruent

5b - 5c = a + 2b

5(15) - 5c = 30 + 2(15)

75 - 5c = 30 + 30

75 - 5c = 60

-5c = -15

c = 3

a + 2b and 10c + d are corresponding angles and congruent

10c + d = a + 2b

10(3) + d = 30 + 2(15)

d + 30 = 60

d = 30

5b - 5c and 2d + 6e are supplementary and add to 180

5b - 5c + 2d + 6e = 180

5(15) - 5(3) + 2(30) + 6e = 180

75 - 15 + 60 + 6e = 180

6e + 120 = 180

6e = 60

e = 10

2d + 6e and 4f + 4e are alt int angles and congruent.

4f + 4e = 2d + 6e

4f + 4(10) + 2(30) + 6(10)

4f + 40 = 60 + 60

4f + 40 = 120

4f = 80

f = 20

3 0
3 years ago
One end point of a line segment is ( -3, -6 ) The length of the line segment is 7 units find four points that could serve as the
Anika [276]

Answer:

(4, -6), (-10, -6), (-3, 1), (-3, -13)

Step-by-step explanation:

If we add/subtract t to/from any x/y coordinate, we will form a line segment with length 7. Hence, (4, -6), (-10, -6), (-3, 1), (-3, -13).

3 0
4 years ago
What is x - the square root of -2
Lena [83]
Sqrt(-2), can be written as i * sqrt(2). Thus, our answer is x - i sqrt(2).
4 0
3 years ago
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