Round 0.98356 to the nearest ten thousandth

3² x 3 x 3 x 3= <br><br> Simplified into exponential form

ruslelena [56]

Answer:

Step-by-step explanation:

$3^{2}$ * $3^{1}$ * $3^{1}$ * $3^{1}$

because the bases are all the same.. just add the exponents

$3^{2+1+1+1}$

or

$3^{5}$

6 0

3 years ago

Read 2 more answers

A test is worth 100 points containing 38 problems. Each problem is either 2 points or 5 points. How many of each amount of point

RSB [31]

Answer:

So there are 8 five-point problems and 30 two-point problems

5 0

3 years ago

What is 45 1/2% written as a fraction in simplest form

nirvana33 [79]

<span>45.5% is equivalent to 45.5/100. To remove the decimal from the fraction, multiply both by the same factor of ten so they are integers: 455/1000. This can be cancelled down to 91/200 in its simplest form.</span>

4 0

4 years ago

a kitchen makes 2,944 oz. of soup each week, ther are 128 oz. in 1 gallon. how many gallons of soup does the kitchen make in 2 w

Anna71 [15]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ 46 gallons

2944/128 = 23

23 gal = 1 week

23 x 2 = 46

46 gal = 2 weeks

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

3 0

3 years ago

A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

7 0

3 years ago