Answer:
The graph of y2+3x=0 is symmetric with respect to the x-axis
Step-by-step explanation:
To establish symmetry with respect to the x-axis we simply substitute -y in place of y in the original equation. If the resulting equation is identical to the original one then the function is said to be symmetric with respect to the x-axis.
In this case we have;

Which is identical to the original equation
Answer:
see explanation
Step-by-step explanation:
is in the fourth quadrant
Where sin and tan are < 0 , cos > 0
The related acute angle is 2π -
= 
Hence
sin([
) = - sin(
) = -
= - 
cos(
) = cos(
) = 
tan(
= - tan(
= - 1
Your Welcome!!
(Hopefully they're all right)