What is the value of x?
1 answer:
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The ratio of the volumes is equal to the scale factor cubed.
![\frac{V_1}{V_2}=k^3 \\ \\ \frac{320 \ cm^3}{1080 \ cm^3}=k^3 \\ \frac{8}{27}=k^3 \\ k=\sqrt[3]{\frac{8}{27}} \\ \boxed{k=\frac{2}{3}} \Leftarrow \hbox{answer B}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BV_2%7D%3Dk%5E3%20%5C%5C%20%5C%5C%0A%5Cfrac%7B320%20%5C%20cm%5E3%7D%7B1080%20%5C%20cm%5E3%7D%3Dk%5E3%20%5C%5C%0A%5Cfrac%7B8%7D%7B27%7D%3Dk%5E3%20%5C%5C%0Ak%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B8%7D%7B27%7D%7D%20%5C%5C%0A%5Cboxed%7Bk%3D%5Cfrac%7B2%7D%7B3%7D%7D%20%5CLeftarrow%20%5Chbox%7Banswer%20B%7D)
The inequality would look like this:
-2 (3x + 2)
-6x-4
To begin to find the solutions, distribute the -2 throughout the set of parenthesis on the left side of the inequality by multiplying the -2 by each term in the set of parenthesis
-2 x 3x = -6x
-2 x 2 = -4
-6x -4-6x-4
Begin to isolate x by performing the opposite operation of adding -6x on both sides of the inequality
0x -4-4
Next perform the opposite operation by adding 4 on both sides of the inequality
0x 0
Now, I'm not exactly understanding how that can possibly work. So, I guess I didn't really help you. But add a comment so that we can talk about the problem :)
-2 (3x + 2)
To begin to find the solutions, distribute the -2 throughout the set of parenthesis on the left side of the inequality by multiplying the -2 by each term in the set of parenthesis
-2 x 3x = -6x
-2 x 2 = -4
-6x -4
Begin to isolate x by performing the opposite operation of adding -6x on both sides of the inequality
0x -4
Next perform the opposite operation by adding 4 on both sides of the inequality
0x
Now, I'm not exactly understanding how that can possibly work. So, I guess I didn't really help you. But add a comment so that we can talk about the problem :)