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3 years ago

What are the coordinations of the image of triangle ABC after it is translated (x,y) (x+2, y-4)

Mathematics

1 answer:

erastovalidia [21]3 years ago

7 0

Answer:

A.(-3,2) B(1,5) C(2,-3) < Original coordinates

Translation being used: (x, y ) → (x + 2, y - 4)

First: You would take your x coordinates and add two to them because that is the translation being used to solve for your x coordinate.

You would get for your x's: A (-1,_) B (3,_) C (4,_)

Next: You would take your y coordinates and subtract four from each because that is the translation being used to solve for your y coordinate.

You would get for your y's: A (_, -2) B (_, 1) C (_, -7)

Last: You would take each one and out it together, or piece it basically.

Your answer would be: A (-1, -2) B (3, 1) C (4, -7)

HOPE THIS HELPS! ^_^

Step-by-step explanation:

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3 years ago

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ra1l [238]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam

Serjik [45]

Answer:

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that $n = 75$ and $\pi = \frac{44}{75} = 0.586$ .

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291$

The upper limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429$

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

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3 years ago

(x+2)(x+6)=0

Mkey [24]

Here ya go.

Answer in picture

6 0

3 years ago