v squared minus 4v minus 21over 3v squared plus 6v times v squared plus 8v over v squared plus 11v plus24
1 answer:
You might be interested in
Answer:
wives
sacks
cats
kits
Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.
Step-by-step explanation:
wives
If each of the "x" wives has "x" sacks, so the number of sacks is:
sacks
If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:
cats
If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:
kits
Option first and option second are correct because the common difference of the sequence is the same as the slope of the graph.
<h3>What is a sequence?</h3>
It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.
The question is incomplete.
The question is:
What can be concluded about the sequences 19, 15, 11, 7, . . . represented on the graph? Check all that apply.
- The common difference of the sequence is the same as the slope of the graph.
- The slope of the graph is –4.
- The next term in the sequence is represented by point (4, 3).
- f(x) = –4x + 19 represents the sequence.
- An infinite number of points can be determined to follow this sequence.
The graph is attached to the picture please refer to the graph.
We have an arithmetic sequence:
19, 15, 11, 7,...
The first term is:
a = 19
Common difference d = 15-19 = -4
The nth term:
a(n) = 19 + (n-1)(-4)
a(n) = 19 -4n + 4
a(n) = -4n + 23
We can write above expression as:
f(x) = -4x + 23
Slope of the equation = -4
The correct options are:
- The common difference of the sequence is the same as the slope of the graph.
- The slope of the graph is –4.
Thus, an option first and option second are correct because the common difference of the sequence is the same as the slope of the graph.
Learn more about the sequence here:
#SPJ1
