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irga5000 [103]
3 years ago
10

What is the partial product of 434x310

Mathematics
2 answers:
djyliett [7]3 years ago
6 0
<span>What is the partial product of 434 x 310
</span>

<span>should be
4340 and 130200

4340 + 130200 = </span>434 x 310 = 134540
umka21 [38]3 years ago
5 0
Hey! Hope that I can help. Answer: 48,540

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32.13

Step-by-step explanation:

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Divide. Write your answer using the smallest numbers possible.
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Step-by-step explanation:

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In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
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Answer:

0.071,1.928

Step-by-step explanation:

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Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

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Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

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Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

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Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
3 years ago
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3 0
3 years ago
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