The function
f(x) is even
g(x) is neither even nor odd
h(x) is odd
Steps:
for an even function it holds that f(-x) = f(x):
f(-x) = (-1)^6 x^6 - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even
for an odd h(x) it holds that h(-x) = -h(x):
It is easy to show that g(x) does not match any of the two possibilities above.
G(-4)
=1/2((-4)-1)
=1/2(-5)
=-2.5
------------------------------
f(g(-4))
=f(-2.5)
=2(-2.5)+1
=-5+1
=-4
Hey there!
"What ratio forms a proportion with ?"
- (for the decimal)
But in order for you to solve this particular equation you'd have to go in with two (like multiplying by two)
Your result:
Good luck on your assignment and enjoy your day!
~
(-3)(8+-10)
(-3) • ( -2)
which equals 6
You will factor out the common factor of t if you are solving for t. you will then divide both sides by (s+3) to make t the subject of the formula. for this question you can only get t in terms of s.
so:
st+3t=6
t(s+3)/(s+3)=6/(s+3)
t=6/(s+3)
if you are required to solve for s then you are going to subtract 3t from both sides. you can factorise 6-3t .you will then divide both sides by t to isolate s.for this question you can only get s in terms of t.so:
st+3t-3t=6-3t
st/t=2(3-t)/t
s=2(3-t)/t