Answer:..Step-by-step explanation:
Answer:
I need more information, meaning his formula.
Step-by-step explanation:
Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
Answer:
x > -2.5
Step-by-step explanation:
1) 5.1 (3 + 2.2x) > -14.25 - 6 (1.7x + 4)
2) 15.3 + 11.22x > -14.25 - 10.2x - 24
3) 15.3 + 11.22x > -38.25 - 10.2x
4) 11.22x + 10.2x > -38.25 - 15.3
5) 21.42x > -53.55
6) x > -2.5
Alternate forms
x > -5/2x or x > -2 1/2
Step-by-step explanation:
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