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Serjik [45]
3 years ago
14

2x-17=9/x solve by factoring

Mathematics
1 answer:
aleksley [76]3 years ago
7 0
X=9, - 1/2 is the answer
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We are interested in the dimensions of a certain rectangle. this rectangle has length twice the side of the square and width thr
Mila [183]
Area of square = s^2
Area of Rectangle = lw
l = 2s

w+3 = s
solve for w, w=s-3
Now we have l and w.
Plug both into area of rectangle formula so: (2s)(s-3)
Since both areas are equal set both equations equal to each other:
(2s)(s-3)=s^2
Now simplify
2s^2-6s=s^2
s^2-6s=0, Solve for s.
Factor polynomial. s(s-6)=0 , s can be equal to 0 or 6. HOWEVER, you cannot have a side length of 0 therefore the side length has to be 6.
Now plug in s for the length formula for the rectangle:
l = 2s so... l = 2(6) so length of rectangle = 12.
Now plug in s for the width formula for the rectangle:
w+3=s so... w+3=6 so width of rectangle = 3.
Now the dimensions of the rectangle are 12 by 3. 12 being length and 3 width.
To CHECK:
Find area of rectangle:
A=lw so A=3 times 12 so A=36
Find area of square:
We know the side is equal to 6 so
A=s^2 so 6^2 = 36
The areas are equal that verifies the answer of 12 by 3.
8 0
3 years ago
The question is what is 4p - 9
OlgaM077 [116]

Answer:

4xp-9

Step-by-step explanation:

4 0
2 years ago
Whats the square footage of 10 by 10​
maria [59]
Answer: 100 square feet

How many square feet is a 10x10 room? The square footage of a room 10 feet wide by 10 feet long is 100 square feet. Find the square footage by multiplying the width (10 ft) by the length (10 ft).
7 0
2 years ago
A drainage pipe 66 in. tall measures 25.12 in. around.
Schach [20]
In order to solve this using V= B(h) (The B is area of the base) you need a radius it doesn't give us that but it does give us the circumference. 
C= 3.14(2r)
25.12=2r divide each by 2 
12.56=r
now use this in the volume formula:
V= 12.56^2(3.14)(66)
V=32,692.86 cubic inches 
8 0
3 years ago
Evaluate:<br> (-4x+6) + (x-5)
Lady bird [3.3K]

Answer:

-3x+1

Step-by-step explanation:

8 0
3 years ago
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