probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
Answer:
5/6 books
Step-by-step explanation:
We know that Mark read 2 1/2 books last week. This week, he read a bit more with 3 1/3 books.
To find how many more books he read, we must subtract 2 1/2 from 3 1/3:
3 1/3 - 2 1/2
Let's convert these into improper fractions first:
3 1/3 = (3 * 3 + 1) / 3 = 10/3
2 1/2 = (2 * 2 + 1) / 2 = 5/2
Now, we have:
10/3 - 5/2
In order to subtract these, we must find a common denominator. For 2 and 3, the LCM is 6, so we can use that as our common denominator:
10/3 * 2/2 = 20/6
5/2 * 3/3 = 15/6
Finally, we have:
20/6 - 15/6 = (20 - 15) / 6 = 5/6 books
Answer:It should be D E F since they all are closer to 1
Step-by-step explanation:
Am not 100% sure but I think it’s A
Answer:
B because they are basically the same AB = 2, there was no change, just a relfection, so A'B' = 2 as well Hope this helped
Step-by-step explanation:
