I think it’s the last one
we know that
The <u>Triangle Inequality Theorem</u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side
so
Let
s------> the length of the third side

therefore
<u>The answer part a) is</u>

we know that
the perimeter of a triangle is the sum of the length sides
In this problem

<u>For
</u>
the perimeter is equal to

<u>For
</u>
the perimeter is equal to

so

therefore
<u>the answer part b) is</u>

Answer:
See below
Step-by-step explanation:
a. here you are to multiply the two functions together:

b. here you are to subtract g from f:

c. here you are to compose g into f. In other words, pick up the whole g function and plug it into f wherever you see an x:

d. here you are compose f into g. In other words, pick up the whole f function and plug it into g wherever you see an x:

You now have to FOIL out the (3x-1) like so:
![2[(3x-1)(3x-1)]](https://tex.z-dn.net/?f=2%5B%283x-1%29%283x-1%29%5D)
which gives you

Distribute in the 2 and you'll end up with the answer:

Answer:
2<x<4/3
Step-by-step explanation:
Given the equation of a graph to be y = |3x− 5|, if the equation is one unit to the right, this can be expressed as |3x-5| > 1.
Solving the resulting equation
|3x-5| > 1.
Since the function 3x-5 is in a modulus sign, this means that the function can take both negative and positive values.
For positive value of the function;
+(3x-5) > 1
3x > 1+5
3x>6
x>6/3
x>2 ... (1)
For the negative value of the function;
-(3x-5) > 1
On expansion
-3x+5 > 1
-3x > 1-5
-3x > -4
Multiplying through by -1 will also change the inequality sign
x < -4/-3
x < 4/3...(2)
Combining equation 1 and 2, we have;
2<x<4/3
One of the easiest methods that can be used to find the area of a polygon is to split the figure into triangles