A city lot is 20 4/5 meters wide. It is 2 1/2 times as long as it is wide. How long is the city lot? Express your answer in simp
2 answers:
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Answer:
i. ΔAXC ~ ΔCXB
ii. ΔBCX Is-congruent-to ΔACX
Step-by-step explanation:
From the given ΔABC, CX is the altitude of ΔABC; and also an angle bisector of <ACB.
So that:
m<AXC = m<BXC (right angle property)
m<ACX = m<BCX (congruent property)
m<ACX + m<AXC + m<CAX = (sum of angles in a triangle)
m<BCX + m<BXC + m<CBX = (sum of angles in a triangle)
Therefore, from the figure it can be deduced that;
i. ΔAXC ~ ΔCXB (Angle-Angle-Side, AAS, property)
ii. ΔBCX Is-congruent-to ΔACX (Angle-Angle-Side, AAS, property)