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Travka [436]
1 year ago
5

Joe thinks the area to be pantries on wall 2is 84 square feet.

Mathematics
1 answer:
lilavasa [31]1 year ago
7 0

<u>Please</u><u> </u><u>put</u><u> </u><u>a</u><u> </u><u>picture</u><u> </u><u>next</u><u> </u><u>time</u><u> </u><u>:</u><u>)</u>

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2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
If y= -3x7+2x3+ x, the derivative of y with respect to x is
larisa [96]

Answer:

\frac{dy}{dx} = - 21x^{6} + 6x² + 1

Step-by-step explanation:

Differentiate each term using the power rule

\frac{d}{dx} (ax^{n} ) = nax^{n-1}

Given

y = - 3x^{7} + 2x³ + x , then

\frac{dy}{dx} = (7 × - 3 )x^{6} + (3 × 2)x² + (1 × 1 )x^{0}

    = - 21x^{6} + 6x² + 1

8 0
3 years ago
BAC ~ DEC what is the value of x?
Anna007 [38]

Answer: x = 37.8

Step-by-step explanation: We start with triangle ABC with two sides given as 15 and 18. We shall make angle C the reference angle and thereby calculate the third side, line BC.

Since we have the opposite side as 15, and the adjacent side (which lies between the reference angle and the right angle) as 18, we can use the tangent of the angle C

Tan C = Opp/Adj

Tan C = 15/18

Tan C = 0.8333

From our table of values/use of the calculator

Tan C = 39.8

Angle C in triangle ACB = Angle C in triangle ECD (Opposite angles are equal).

That takes us to triangle ECD, since the reference angle is known (39.8) and the opposite side is also given (31.5), we can now calculate the adjacent which is side x.

Tan C = Opp/Adj

Tan 39.8 = 31.5/x

when you cross multiply, x moves to the left hand side, while Tan 39.8 moves to the right hand side

x = 31.5/Tan 39.8

x = 31.5/0.8333

<u>x = 37.8</u>

5 0
3 years ago
Need help solving this differentiation problem please. Thank you.
DIA [1.3K]
First convert the terms to fractional exponents

u  =  t^2/3  - 3t^3/2

differentiating

u'  =  2/3 t^ (2/3 - 1) - 3* 3/2  t^(3/2 - 1)

     =  2/3 t ^(-1/3) - 9/2 t ^(1/2)

     =  2 / (3∛t) -  9 √ t / 2   in radical form


7 0
3 years ago
Read 2 more answers
3<br> x x &lt; – 6 or 5x &gt; 2<br> 8
Roman55 [17]

Answer:

is this a question .....write it correctly

8 0
3 years ago
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