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3 years ago

Josiue tosses a coin and spins the spinner at the right. What are all the possible outcomes?

1 answer:

6 0

The possible outcomes for the coin is 2 out of 1 since a coin has 2 sides the coin may only land on 1 side but the chances are between both sides having a 50/50 chance to land on either side.

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Write an equation of the line in point-slope form that passes through the given points.

RSB [31]

Answer:

Step-by-step explanation:

point - slope formula: y - y1 = m(x-x1)

we need to find the slope ... or what is m ?

m = rise / run

m = y2 - y1 / x2 - x1

where the given points are (x1,y1) and (x2,y2)

m= 7-5 / 6-5

m = 2 / 1

m =2

now use either point and plug the slope and the point into the point-slope formula

y-5 =2(x-5) :)

5 0

3 years ago

HURRY ASAP IM ABT TO TURN THIS IN

Lina20 [59]

The answer would be -1

4 0

3 years ago

Read 2 more answers

What is the length of segment GH? Round to the nearest hundredth.

stepan [7]

43.57 hope this helps.

6 0

4 years ago

Read 2 more answers

Solve for xxx. Enter the solutions from least to greatest.<br> x^2 + x - 30 = 0x <br> 2<br> +x−30=0

AfilCa [17]

Given:

The quadratic equation is:

$x^2+x-30=0$

To find:

The solutions of the given equation.

Solution:

We have,

$x^2+x-30=0$

Splitting the middle term, we get

$x^2+6x-5x-30=0$

$x(x+6)-5(x+6)=0$

$(x+6)(x-5)=0$

Using zero product property, we get

$x+6=0$ and $x-5=0$

$x=-6$ and $x=5$

Therefore, the solutions of the given quadratic equation are -6 and 5.

6 0

3 years ago

You are going camping with your family for a family reunion. You need to know how many sleeping bags will fit inside the tent yo

Svetach [21]

Answer:

a. $A_{trapezoid}=228ft^2$

b. $A_{trapezoid}=228ft^2$

c. They are equivalent

Step-by-step explanation:

a. The trapezoid can be divided into two triangles and one rectangle. For the three figures, the height is 12ft. For the rectangle, the dimensions are 12ftx10ft. Since the legs are of the same length the triangles have a base of 9ft (because the rectangle takes 10 feet from the base of 28 feet and there are 18 feet left over, these 18 are divided equally between the two triangles).

$A_{rectangle}=bh=(10)(12)=120ft^2$

$A_{triangle}=\frac{bh}{2}=\frac{9(12)}{2}=\frac{108}{2}=54ft^2$

$A_{trapezoid}=A_{rectangle}+A_{triangle}+A_{triangle}\\Area=120+54+54=228ft^2$

b. The formula is

$A=h(\frac{B+b}{2})=12(\frac{10+28}{2})=12(19)=228ft^2$

c. They are equivalent

4 0

4 years ago