Answer:
The test statistic z = z = 2.368 >1.97 (at 5% level of significance)
we rejected null hypothesis at 5% level of significance
There is significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.
Step-by-step explanation:
Given data In a study to estimate the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear power plant, it is found that 63 of 100 urban residents
The first sample proportion
The construction of 59 of 125 suburban residents are in favor
The second sample proportion
Given the sample sizes are n₁ = 100 and n₂ =125
<u>Null hypothesis(H₀):</u>-there is no significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.
<u>Alternative hypothesis: H₁</u>
There is significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.
<u>Level of significance</u>:-
∝ =0.05
Tabulated value z=1.96
<u>Test statistic</u>
<u></u><u></u>
where q = 1- p
Substitute all values in above equation
q = 1-p = 1 - 0.542 = 0.458
The test statistic
on simplification , we get
z = 2.368 >1.97 (at 5% level of significance)
we rejected null hypothesis at 5% level of significance
<u>Conclusion</u>:-
There is significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.
