Step-by-step explanation:
Explanation is in the attachment
hope it is helpful to you
If we expand bx to jx and kx we have:
5y^2-2y-7
5y^2-7y+5y-7 then factor...
y(5y-7)+1(5y-7)
(y+1)(5y-7)
So the other factor is:
(y+1)
For this case we have that by definition, the standard form of the equation of the line is given by:

We have the following equation:

We manipulate the equation algebraically:

Finally, the equation is:

Answer:
