All categories

3 years ago

Find the area of a polygon with the vertices of A (0,1) B (0,5) C (4,5) D (6,1

Mathematics

1 answer:

butalik [34]3 years ago

5 0

Your area is 25 square units

You might be interested in

Find the derivative of y= 1 / x

givi [52]

Answer:

dy/dx = -1/ $x^{2}$

Step-by-step explanation:

y = 1/x

dy/dx = d/dx(1/x)

=> dy/dx = d/dx( $x^{-1}$ )

=> dy/dx = - $x^{-2}$

=> dy/dx = -1/ $x^{2}$

6 0

2 years ago

If 2a+3<10 then which of these could be a value of a

solmaris [256]

Answer:

a < 3.5

Step-by-step explanation:

2a+3 <10

subtract 3 from each side

2a +3 -3 < 10-3

2a < 7

divide by 2

a < 7/2

a < 3.5

6 0

2 years ago

What's the square root of 2 rounded to the nearest tenth ?

vichka [17]

It is 1.4 when rounded

8 0

3 years ago

Read 2 more answers

Mia tossed a penny, a nickel, and a dime. Which is a complete tree diagram for all possible outcomes, where H represents heads a

Novay_Z [31]

Mia tossed a penny,a nickel and a dime all possible outcomes of H is the answer C.

Step-by-step explanation:

The two possible outcomes for penny,nickel and dime is H & T.
H is for head T is for tail.
Let A {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
Tossing a fair coin will give the above result.
S is the called the n number of outcomes that are available for a set.
Total outcome of Sample space 8.
The three diagram is like a game theory it exploits different outcome.

8 0

3 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago