If a variable is binomially distributed with n trials and a success probability of p, then the mean = np, variance = np(1–p) and standard deviation = square root of variance.
In this case, n = 1200, p = 0.35. So, mean = (1200)(0.35) = 420,
variance = (1200)(0.35)(1–0.35) = 273,
standard deviation = square root of variance = √273 = 16.52.
This probability is the same as 1-(two different suited cards). Your first card can be any of the 52 cards. Your second card must be any of the 39 different suited remaining 51 cards. So the answer is 1 - (52/52)(39-51). Note: I assumed there was no replacement.
Answer:
Step-by-step explanation:
Let's do the obvious things first.
Right rectangle
w = 11
L = 17
Formula
Area = L * W
Area = 11 * 17
Area = 187
Left rectangle
W = 8
L = 11
Area = 8 * 11= 88
Middle Rectangle
W = 11
L = 15
Area = 11 * 15 165
Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)
There are 2 triangles
Area = 2 * 1/2 * l1 * l2
Leg 1 = 8
Leg2 = 15
Area = 2 * 1/2 (8 * 15)
Area = <u> 120 </u>
Total = 120 + 165 + 88 + 187 = 560
Unless you have an E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.
1.Disc method.
In this method the volume is given by:
![\boxed{V=\pi\int\limits_a^b\big[f(x)\big]^2}](https://tex.z-dn.net/?f=%5Cboxed%7BV%3D%5Cpi%5Cint%5Climits_a%5Eb%5Cbig%5Bf%28x%29%5Cbig%5D%5E2%7D)
so:
![V=\pi\int\limits_1^3x^4\,dx=\boxed{\pi\int\limits_1^3\big[x^2\big]^2\,dx}](https://tex.z-dn.net/?f=V%3D%5Cpi%5Cint%5Climits_1%5E3x%5E4%5C%2Cdx%3D%5Cboxed%7B%5Cpi%5Cint%5Climits_1%5E3%5Cbig%5Bx%5E2%5Cbig%5D%5E2%5C%2Cdx%7D)
A) Function

over the interval
![[1,3]](https://tex.z-dn.net/?f=%5B1%2C3%5D)
B) We use disk method and f(x) is function of variable x, so we <span>rotate the curve about the x-<span>axis.
2. Shell method.
In this case volume is given by:
</span></span>

So there will be:

A) Function

over the interval
![[1,3]](https://tex.z-dn.net/?f=%5B1%2C3%5D)
B) We use shell method and f(x) is function of variable x, so we <span>rotate the curve about the y-<span>axis.</span></span>