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makvit [3.9K]
2 years ago
10

Show me how to find x using the correct equation shown here (geometry)

Mathematics
1 answer:
scoundrel [369]2 years ago
7 0

Answer:

13

Step-by-step explanation:

Angles ( 12x - 29 ) and ( 4x + 1 ) are co - interior angles.

Sum of co - interior angles is supplementary.

12x - 29 + 4x + 1 = 180

12x + 4x - 29 + 1 = 180

16x - 28 = 180

16x = 180 + 28

16x = 208

x = 208 / 16

x = 13

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The lengths of the sides of a triangle are in a the extended ratio of 3:6:8. The triangles perimeter is 510cm. What are the leng
lisov135 [29]
I think
(Total)
3 : 6 : 8 = 17
(Times by 30 to get total then you times by each ratio/side)


90 : 180 : 240= 510cm
6 0
3 years ago
a box cost $2.48, but it is on sale for $1.49. How much do you save on one box when bought on sale? Now how much would you save
Thepotemich [5.8K]

Answer:

1. $0.99

2. $1.98

Step-by-step explanation:

1. From the question we have

Cost of box = $2.48

Selling price = $1.49

That is the box is discounted from $2.48 to $1.49

Therefore, amount saved = $2.48 - $1.49 = $0.99

2. The amount saved from buying a second box is hence;

2 × $0.99 = $1.98

Hence, as the number of boxes bought increases, the amount saved increases

5 0
3 years ago
Read 2 more answers
Maureen earned some money doing odd jobs last summer and put it in a savings account that earns 9% interest compounded quarterly
ivolga24 [154]

Answer:

Maureen earned $123.19 doing odd jobs

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit year and t is the time in years for which the money is invested or borrowed.

In this question:

Compounded quarterly means that n = 4

10 years, so t = 10

9% interest, so r = 0.09

There is $300.00 in the account, which means that A = 300

How much did Maureen earn doing odd jobs?

This is P.

A(t) = P(1 + \frac{r}{n})^{nt}

300 = P(1 + \frac{0.09}{4})^{4*10}

(1.0225)^{40}P = 300

P = \frac{300}{(1.0225)^{40}}

P = 123.19

Maureen earned $123.19 doing odd jobs

5 0
3 years ago
What is z- 4/4 +8 simplified?​
vova2212 [387]

Answer:

aw baby naw that not cool

Step-by-step explanation:

3 0
2 years ago
After all your hard work studying for Algorithms you, Alice and Bob end up stuck in a room full of deadly zombies! Luckily you h
shutvik [7]

Answer:

The most important quantity to consider in order to answer this question is the arrival time of the zombies from their initial position, which is the quotient between their distance to the visitors, divided the zombie's speed.

See explanation below.

Step-by-step explanation:

Part 1)

What is crucial to know is what is the time at which each zombie would reach Alice and Bob, and that is given by the quotient between the distance away each zombie is, divided by the zombie's speed:

speed=\frac{distance}{time} \\time=\frac{distance}{seed} \\t_i=\frac{d_i}{s_i}

Then, it is this quotient for each zombie, that one has to estimate given the input values distance and speed, and it is the output "time" (t_i) for each zombie, what we need to analyze so as to prioritize an order regarding which zombie to kill first.

Part 2)

Shooting the closest zombie first is not a good idea, since the speed of that closest zombie may be much slower than another zombie further away, but with much larger speed. Again, the important value to analyze is the time that it would take each zombie to reach Alice and Bob.

Part 3)

Shooting the fastest zombie first is not a good idea either, because that fastest zombie could be located very far away from the visitors, and other zombies closer by may reach them first.

Part 4)

The order that should be used to kill the zombies is given by the value of the time to reach Bob and Alice based on the quotient distance (di) over speed (si) explained in Part 1). The zombie that shows smallest time should be shot first, and then the others in increasing order of time value.

Part 5)

Notice that the individual zombie information is not presented in the question, but the student should be able to calculate the quotients for each zombie, and considering that there could be at most one shot every second, estimate the number of seconds that the time for each zombie in increasing order would allow until the addition of shooting time per second in the appropriate order cannot match the arrival time of the zombies that are left.

One should count number of seconds from the first shot (to the zombie with shortest arrival time), and then increase in one unit (one shot per second), to the following zombie with slightly larger arrival time), and so on, until the addition of seconds (one second per shot and per increasing arrival time of zombie) exceeds the next zombie arrival time.

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