Answer:
40.6944 is your answer
Step-by-step explanation:
3.6×3.14=11: 3.6×3.6=40.6944 /41
<span>Length of outer track = sum of length of 10 pieces = circumference of the outer circle
if R is the Radius of outer circle then...
Circumference of the outer track = 2pi*R
Similarly the circumference of the inner track (with radius r) = 2pi*r
length of each outer piece is 3.4 inch more than length of inner piece
So total outer length is 10*3.4 =34 inches more than the inner length.
=> Outer Circumference - Inner Circumference = 34 inches
=> 2pi*R - 2pi*r = 34
=> 2pi(R -r) = 34
=> R-r = 34/2pi = 5.41 inches
=> R-r = Width of the track = 5.41 inches</span>
Answer:
Step-by-step explanation:
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Answer:
Step-by-step explanation:
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Answer:
PQ = 5 units
QR = 8 units
Step-by-step explanation:
Given
P(-3, 3)
Q(2, 3)
R(2, -5)
To determine
The length of the segment PQ
The length of the segment QR
Determining the length of the segment PQ
From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.
so
P(-3, 3), Q(2, 3)
PQ = 2 - (-3)
PQ = 2+3
PQ = 5 units
Therefore, the length of the segment PQ = 5 units
Determining the length of the segment QR
Q(2, 3), R(2, -5)
(x₁, y₁) = (2, 3)
(x₂, y₂) = (2, -5)
The length between the segment QR is:




Apply radical rule: ![\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%2C%5C%3A%5Cquad%20%5Cmathrm%7B%5C%3Aassuming%5C%3A%7Da%5Cge%200)

Therefore, the length between the segment QR is: 8 units
Summary:
PQ = 5 units
QR = 8 units