Find the angles of a triangle whose two base angles are equal and whose third angle is 10° less than three times the base angle.
2 answers:
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Answers:
P(A) = 7/12
P(B) = 1/2
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Explanation:
To see how I calculated P(A), check out this link to this very similar question
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Now to calculate P(B)
If a number is divisible by 2, then the number is a multiple of 2.
In other words, the number is even.
Counting through the values in the table, you should find that there are 18 sums that are even (2, 4, 6, 8, 10 and 12). Refer to the dice chart below.
Here's a further breakdown
- 1 copy of "2"
- 3 copies of "4"
- 5 copies of "6"
- 5 copies of "8"
- 3 copies of "10"
- 1 copy of 12
Side note: We have nice symmetry going on.
There are 1+3+5+5+3+1 = 18 values total that are even numbers. The other half are odd numbers of course.
P(B) = 18/36 = (1*18)/(2*18) = 1/2
Answer: $ 18681.45
Step-by-step explanation:
Given: Future value :
The rate of interest :
The number of time period :
The formula to calculate the future value is given by :-
, where P is the initial amount deposited.
Hence, the lump that must be deposit today : $ 18681.45
Answer:
Part A
b. 14.6 ± 7.38
Part B
b. 3.43
Part C
a. P-value < 0.01
Part D
b. There is sufficient evidence to reject the null hypothesis
Step-by-step explanation:
Part A
The given data are;
The number of seedlings in the field = 20
The number of seedlings selected to receive herbicide A = 10
The number of seedlings selected to receive herbicide B = 10
The height in centimeters of seedlings treated with Herbicide A, = 94.5 cm
The standard deviation, s₁ = 10 cm
The height in centimeters of seedlings treated with Herbicide B, = 109.1 cm
The standard deviation, s₂ = 9 cm
The 90% confidence interval for μ₂ - μ₁, is given as follows;
The critical-t at 95% and n₁ + n₂ - 2 degrees of freedom is given as follows;
The degrees of freedom, df = n₁ + n₂ - 2 = 10 + 10 - 2 = 18
α = 100% - 90% = 10%
∴ For two tailed test, we have, α/2 = 10%/2 = 5% = 0.05
= 1.734
C.I. ≈ 14.6 ± 7.37714603353
The 90% C.I. ≈ 14.6 ± 7.38
b. 14.6 ± 7.38
Part B
With the hypotheses are given as follows;
H₀; μ₂ - μ₁ = 0
Hₐ; μ₂ - μ₁ ≠ 0
The two sample t-statistic is given as follows;
The two sample t-statistic ≈ 3.43
b. 3.43
Part C
From the t-table, the p-value, we have, the p-value < 0.01
a. P-value < 0.01
Part D
Given that a significance level of 0.05 level is used and the p-value of 0.01 is less than the significance level, there is enough statistical evidence to reject the null hypothesis
b. There is sufficient evidence to reject the null hypothesis.