I don't think it can be reduced anymore.
The number of presale tickets sold is 271
<em><u>Solution:</u></em>
Let "p" be the number of presale tickets sold
Let "g" be the number of tickets sold at gate
<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>
Therefore,
Presale tickets + tickets sold at gate = 800
p + g = 800 ------ eqn 1
<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>
Therefore,
Number of tickets sold at gate = twice the number of pre-sale tickets - 13
g = 2p - 13 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
p + 2p - 13 = 800
3p -13 = 800
3p = 800 + 13
3p = 813
p = 271
Thus 271 presale tickets were sold
Answer:
4 1/3 cups
Step-by-step explanation:
All you have to do for this one is subtract 5 2/3 from 10, which is 4 1/3. Your equation could be 10-5 2/3=x.
C - the value of 2 in Venus' distance is 1/10 the value of earth's distance.
The 2 in Venus' distance represents 200,000
The 2 in Earth's distance represents 2,000,000
Venus's 2 is 1/10 the value of earth's