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White raven [17]
3 years ago
12

Which of the following are true?

Mathematics
1 answer:
Kitty [74]3 years ago
6 0

Answer: c).

Both options are true. You can see that the whiskers of data set 2 (The lines extending on either side of the box plots) represent a much larger range of data than data set 1, and that the median in data set 2 (the line down the middle of the boxes) is greater than data set 1.

Hope this helps!

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7g + 4g + 3g − 13g + g = 10 please help!!
Leona [35]
Combine like terms.


7g + 4g + 3g + g = 15g

15g - 13g = 2g


2g = 10


Divide by 2 on both sides.


g = 5
5 0
3 years ago
Read 2 more answers
What is the sum of the seven terms of the geometric series 2- 8+32-...?
egoroff_w [7]
The first term is 2 and the common ratio = -8/2 = -4

S7   = 2 * (-4)^7 - 1
                -------------    =      6554   answer
                  -4-1
6 0
3 years ago
What is the area of a parrallegram of 8cm and 4cm?
scoundrel [369]
How you would solve it is by 8 multiplied by 4.
The formula B*H
So the answer is 32cm squared.
3 0
3 years ago
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Why is it not reasonable to have a linear trinomial with only one type of letter?
Rus_ich [418]
Because you can just simplify to have 1-2 terms only. Eg:
13+2y+4y (this is a trinomial as it has 3 terms) can be simplified to just give 13+6y
5 0
3 years ago
Use synthetic division and remainder theorem p(x) = 3x^3 - 5x^2 - x + 2. p(-1/3)=
Alik [6]

Answer:

5/3

Step-by-step explanation:

-1/3 goes on the outside and since we have our polynomial in standard form with no in between terms missing, 3,-5,-1,2 go inside because they are the coefficients of our polynomial.

-1/3   |   3      -5          -1          2

       |

         -------------------------------------

First step bring the 3 down inside. (3+0=3)

-1/3   |   3      -5          -1          2

       |

         -------------------------------------

           3

Whatever goes below the bar, must be multiplied by outside number and put directly below next number inside.

-1/3   |   3      -5          -1          2

       |             -1

         -------------------------------------

           3

The numbers lined up vertically are added to get the numbers underneath the bar.

-1/3   |   3      -5          -1          2

       |             -1

         -------------------------------------

           3        -6

Again any number below the bar gets multiply to the number outside.

-1/3   |   3      -5          -1          2

       |             -1          2

         -------------------------------------

           3        -6

Again the numbers lined up vertically above the bar get added to get the number that goes underneath the bar there.

-1/3   |   3      -5          -1          2

       |             -1          2

         -------------------------------------

           3        -6          1

Multiply to outside number 1(-1/3)=-1/3.

This goes under the 2 inside.

-1/3   |   3      -5          -1          2

       |             -1          2          -1/3

         -------------------------------------

           3        -6          1

The last number we are fixing to be put is the remainder of (3x^3-5x^2-x+2)/(x+1/3) or you could say it is the value of p(-1/3) since:

P(x)/(x-c)=Q(x)+R/(x-c)

Multiply both sides by (x-c):

P(x)=Q(x)(x-c)+R

If you evaluate P at x=c, we get R:

P(c)=Q(c)(c-c)+R

P(c)=Q(c)*0+R

P(c)=R.

Let's finish:

-1/3   |   3      -5          -1          2

       |             -1          2          -1/3

         -------------------------------------

           3        -6          1         5/3

This means p(-1/3)=5/3.

We could have also got this by directly plugging in (-1/3) for x into 3x^3-5x^2-x+2.

7 0
3 years ago
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