1)The average acceleration of eagle is 1.75 m/s².
2) The average acceleration of roller coaster is 6 m/s².
3)Acceleration in m/s² is 4 m/s².
4) Acceleration required to stop the car is -17.9 m/s².
5) Acceleration required to stop the car is -8.78 m/s².
6) Acceleration of the plane is 2.87 m/s².
7)Acceleration of the sled is 243 m/s².
Answer:
Explanation:
1) Average acceleration is equal to the rate of change in velocity with respect to time. Here the final and initial velocities are given as 22 m/s and 15 m/s respectively and the time is given as 4 seconds.
So, average acceleration = (Final velocity-Initial velocity)/Time
Average acceleration = (22-15)/4= 1.75 m/s².
Thus, the average acceleration of eagle is 1.75 m/s²
2) Similarly we have to use the above formula for determining the average acceleration of the roller coaster. Here the initial velocity is 4 m/s and final velocity is 22 m/s and the time taken to reach this final speed is 3 seconds.
So, average acceleration = (Final velocity-Initial velocity)/Time
Average acceleration = (22-4)/3= 6 m/s².
Thus, the average acceleration of roller coaster is 6 m/s².
3) Acceleration = 26.8/6.7=4 m/s².
Acceleration in m/s² is 4 m/s².
4) Acceleration required to stop the car = -35.8/2=-17.9 m/s².
Acceleration required to stop the car is -17.9 m/s².
5) Acceleration of the car skidding to stop = (0-22.4)/2.55=-8.78 m/s².
Acceleration required to stop the car is -8.78 m/s².
6) Acceleration of the plane= 88.3/30.8=2.87 m/s².
Acceleration of the plane is 2.87 m/s².
7) Acceleration of the sled = 444/1.83=243 m/s².
Acceleration of the sled is 243 m/s².
