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lara31 [8.8K]
3 years ago
9

If a woman weighs 125 lb, her mass expressed in kilograms is x kg, where x is

Physics
2 answers:
almond37 [142]3 years ago
8 0
Weight of the women in pounds = 125 lb 
1 kg is heavier than 1 pound and 1 Kilogram is same as 2.20462 pounds.  
So 125 lb gives 125 / 2.20462 kilo grams = 56.699 kg and the value is less than 125.
adelina 88 [10]3 years ago
3 0
The first thing you should know to solve this problem is the conversion of pounds to kilograms:
 1lb = 0.45 Kg
 We can solve this problem by a simple rule of three
 1lb ---> 0.45Kg
 125lb ---> x
 Clearing x we have:
 x = ((125) / (1)) * (0.45) = 56.25 Kg.
 Answer
 her mass expressed in kilograms is 56.25 Kg.
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A pipe of length 6.8 m is closed at one end and sustains a standing wave at its second overtone. determine the distance between
r-ruslan [8.4K]
For a pipe closed at one end, the second overtone is the 3rd natural frequency as shown in the diagram.

For the fundamental frequency,
λ = 4L
where
λ = wavelength
L = the length of the tube

For the second overtone (3rd frequency)
λ = (4/3)L

Because L = 6.8 m, therefore
λ = (4/3)*(6.8 m) = 9.0667 m

The distance between a node and an adjacent antinode is λ/2, which is
9.0667/2 = 4.533 m

Answer: 4.5 m

8 0
3 years ago
ASAP pls answer right I will mark brainiest . All I know is 4. Is A
Sonja [21]

Answer:

Q1: B.2 Q2: B.Waxing crescent Q3: A.Waxing Gibbous

Explanation:

4 0
3 years ago
A 12,500 N alien UFO is hovering about the surface of Earth. At time , its position can be given as () = ((0.24 m/s^3)^3 + 25 m)
stepladder [879]

a) F=(3675i-4543k)N

b) 5843 N

Explanation:

a)

The position of the UFO at time t is given by the vector:

r(t)=(0.24t^3+25)i+(4.2t)j+(-0.43t^3+0.8t^2)k

Therefore it has 3 components:

r_x=0.24t^3+25\\r_y=4.2t\\r_z=-0.43t^3+0.8t^2

We start by finding the velocity of the UFO, which is given by the derivative of the position:

v_x=r'_x=\frac{d}{dt}(0.24t^3+25)=3\cdot 0.24t^2=0.72t^2\\v_y=r'_y=\frac{d}{dt}(4.2t)=4.2\\v_x=r'_z=\frac{d}{dt}(-0.43t^3+0.8t^2)=-1.29t^2+1.6t

And then, by differentiating again, we find the acceleration:

a_x=v'_x=\frac{d}{dt}(0.72t^2)=1.44t\\a_y=v'_y=\frac{d}{dt}(4.2)=0\\a_z=v'_z=\frac{d}{dt}(-1.29t^2+1.6t)=-2.58t+1.6

The weight of the UFO is W = 12,500 N, so its mass is:

m=\frac{W}{g}=\frac{12500}{9.8}=1276 kg

Therefore, the components of the force on the UFO are given by Newton's second law:

F=ma

So, Substituting t = 2 s, we find:

F_x=ma_x=(1276)(1.44t)=(1276)(1.44)(2)=3675 N\\F_y=ma_y=0\\F_z=ma_z=(1276)(-2.58t+1.6)=(1276)(-2.58(2)+1.6)=-4543 N

So the net force on the UFO at t = 2 s is

F=(3675i-4543k)N

b)

The magnitude of a 3-dimensional vector is given by

|v|=\sqrt{v_x^2+v_y^2+v_z^2}

where

v_x,v_y,v_z are the three components of the vector

In this problem, the three components of the net force are:

F_x=3675 N\\F_y=0\\F_z=-4543 N

Therefore, substituting into the equation, we find the magnitude of the net force:

|F|=\sqrt{3675^2+0^2+(-4543)^2}=5843 N

7 0
2 years ago
If a 400-mm diameter pipe with a pipe roughness coefficient of 100 flows full of pressurized water with a head loss of 0.4 ft pe
RoseWind [281]

Answer:

Q = 913.9 gpm

Explanation:

The Hazen Williams equation can be written as follows:

P = \frac{4.52\ Q^{1.85}}{C^{1.85}d^{4.87}}

where,

P = Friction Loss per foot of pipe = \frac{0.4}{1000\ ft} = 4 x 10⁻⁴

Q = Flow Rate in gallon/min (gpm) = ?

d = pipe diameter in inches = (400 mm)(0.0393701 in/1 mm) = 15.75 in

C = roughness coefficient = 100

Therefore,

4\ x \ 10^{-4} = \frac{4.52\ Q^{1.85}}{(100)^{1.85}(15.75)^{4.87}}\\\\Q^{1.85} = \frac{4\ x \ 10^{-4}}{1.33\ x\ 10^{-9}} \\\\Q = (300384.75)^\frac{1}{1.85}

<u>Q = 913.9 gpm</u>

5 0
3 years ago
A machinist is required to manufacture a circular metal disk with area 1900 cm2. (a) What radius produces such a disk? (Round yo
alexgriva [62]

Answer:

24.5987 cm

Explanation:

A = 1900 cm^2

Let r be the radius of disc.

The area of disc is given by

A = π r²

Where, π = 31.4

1900 = 3.14 x r²

r² = 605.095

r = 24.5987 cm

6 0
3 years ago
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