Which physical change in which gas directly to a solid is

A student is preparing to bake a cake at home and places several ingredients on the countertop to use. First he preheats the ove

Evgen [1.6K]

Answer:

baking the cake batter

Explanation:

Baking the cake batter will indicate that chemical change has occurred here. What is a chemical change?

A chemical change is one in which a new kind of matter is formed.
It is usually accompanied by energy either evolution or absorption of energy in form of heat or light or both.
The process is irreversible.
When the batter bakes, a new substance different from the cake mix is obtainable.
We cannot get back the ingredient from this baked cake. It is impossible.
This is good indicator of chemical change.

7 0

3 years ago

Jeff’s father is installing a do-it-yourself security system at his house. He needs to get a device from his workshop that conve

elena55 [62]

The answer is a buzzer. hope this helps. this is the answer because it use electricity to make the sound please award brainliest

7 0

3 years ago

Read 2 more answers

What systems of the body are involved in preparing and eating a sandwich

jek_recluse [69]

The systems of the body involved in preparing and eating a sandwich are :
The skeletal, muscular, and digestive system. They are all directly involved in eating and preparing a sandwich.

5 0

3 years ago

Find the unit vector in the direction of vector B=4i+2j-5k

solmaris [256]

Answer:

$\frac{4}{\sqrt{45} } i\,+\frac{2}{\sqrt{45} } j-\frac{5}{\sqrt{45} } k$

Explanation:

for the unit vector, we need to divide the given vector by its norm, because it should be in the SAME direction as the original vector, but of magnitude "1".

We notice that the norm of the given vector is:

$\sqrt{4^2+2^2+(-5)^2} =\sqrt{45}$

Then, the unit vector becomes:

$\frac{4}{\sqrt{45} } i\,+\frac{2}{\sqrt{45} } j-\frac{5}{\sqrt{45} } k$

7 0

3 years ago

A centrifugal pump is operating at a flow rate of 1 m3/s and a head of 20 m. If the specific weight of water is 9800 N/m3 and th

tamaranim1 [39]

Answer:

The power required by the pump is nearly 230.588 kW

Explanation:

Flow rate of the pump Q = 1 m^3/s

the head flow H = 20 m

specific weight of water γ = 9800 N/m^3

efficiency of the pump η = 85%

First note that specific gravity of water is the product of the density of water and acceleration due to gravity.

γ = ρg

where ρ is density. For water its value is 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

The power to lift this water at this rate will be gotten from the equation

P = ρgQH

but ρg = γ

therefore,

P = γQH

imputing values, we'll have

P = 9800 x 1 x 20 = 196000 W

But the centrifugal pump that will be used will only be able to lift this amount of water after the efficiency factor has been considered. The power of pump needed must be greater than this power.

we can say that

196000 W is 85% of the power of the pump power needed, therefore

196000 = 85% of $P_{p}$

where $P_{p}$ is the power of the pump needed

85% = 0.85

196000 = 0.85 $P_{p}$

$P_{p}$ = 196000/0.85 = 230588.24 W

Pump power = 230.588 kW

3 0

3 years ago

Which physical change in which gas directly to a solid is​

Which physical change in which gas directly to a solid is