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Fittoniya [83]
2 years ago
11

Help trying to figure out the answer

Mathematics
1 answer:
kotykmax [81]2 years ago
4 0
The answer would be both apply
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Please help Fr pleased I’m begging you
andreyandreev [35.5K]

Answer:

y = \frac{3}{8}x - 2

Step-by-step explanation:

<u>The answer to this problem is a simple plug-in of the given values into the slope-intercept formula.</u>

Slope intercept formula: y = mx + b

(m = slope)

(b = y intercept)

If the equation has a slope of m = \frac{3}{8}, then the slope-intercept form would be:

y = \frac{3}{8}x

If the y-intercept of an equation is (0 , -2), then the slope intercept form would be:

y = mx - 2

<u>Putting both of these values into an equation would give option A:</u>

y = \frac{3}{8}x - 2

6 0
2 years ago
What is 34827 x 7 =<br><br> Jasper over here..
kirill [66]

Answer:

243789

Step-by-step explanation:

(34827) 7 = 243789

Hope this helps!

3 0
2 years ago
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Why is 1/2 of 2 equals one whole
algol [13]
Hey There :)

This is because one is half of two. You could also multiply 2 * 0.5= 1, 0.5 represents \frac{1}{2} and two is the whole number. This is how \frac{1}{2} of two equals one.

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3 years ago
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Find the measure of one interior angle of the regular polygon shown below
alisha [4.7K]

Answer:

c

Step-by-step explanation:

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3 years ago
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An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
2 years ago
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