List the term(s) in the following expression:<br> 2x2

(This question is related to the picture question)

UNO [17]

Answer:

5. $f(x) = 10,000 (1.5)^x$

Step-by-step explanation:

==>>We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.

Let's test it

Initial: 10,000

After 1 year

10,000 + (.5*10000)

10,000 + 5000 = 15,000

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After 2 years

15,000 + (.5*15000)

15,000 + 7500 = 22,500

--

Let's try our equation.

$f(x) = 10,000 (1.5)^x$

$x=2$

$10,000(1.5)^2$

$10,000(2.25) = 22,500$

*Edit: I just seen that the question is related to the picture question

6 0

3 years ago

Simplify each expression.<br> (6b3 + 6 - 64) - (863 - 6b4 + 2)

Gelneren [198K]

Answer:

6b^4+6b^3-923

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PROBABILITY PROBLEM: Can anyone check my answers for this?

Julli [10]

A: it would be 2 fives outta 8 then he picked one more bill out so chances are 4 fives outta 16. making it 1/4 of a probability.

7 0

3 years ago

Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv

Natasha2012 [34]

Answer:

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=652.6$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$