Solution :
Given initial velocity, v= 48 ft/s
Acceleration due to gravity, g = 
a). Therefore the maximum height he can jump on Mars is
= 96 ft
b). Time he can stay in the air before hitting the ground is
= 8 seconds
c). Considering upward motion as positive direction.
v = u + at
We find the time taken to reach the maximum height by taking v = 0.
v = u + at
0 = 16 + (12) t
We know that, 
Taking t = , we get
feet
Thus he can't reach to 100 ft as it is shown in the movie.
d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.
Therefore final velocity is = -16 ft/s
Answer: The answer is cosine of that acute angle.
Step-by-step explanation: We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.
In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.
Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.
Now, the ratio is given by
Thus, the ratio is cosine of the acute angle.
Answer:
A) 4π
Step-by-step explanation:
The period of a secant function, f(x)=a*sec(bx+c)+d, is defined as 2π/|b| where b is the distance of the period. Since we know b=1/2 given by the function, then the period is 2π/|1/2|=2π/(1/2)=2π(2/1)=4π.
Add y subtract 6. Ur left with y=x-6
Add the equations and ur left with 2x-10
Answer:
45°
Step-by-step explanation:
3x + 4x + 5x = 180° **
12x = 180° / :12
x = 15°
m<A = 3×15 = 45°
** There is a law that the sum of all the angles in a triangle is equal to 180°
