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3 years ago

Which equation represents a graph with a vertex at (1, –6)?

Mathematics

2 answers:

Harman [31]3 years ago

4 0

this can be explained as b on edg :)

Serga [27]3 years ago

3 0

Are there multiple choices

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Can Julie win if she reads 8 books

bogdanovich [222]

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Yes, she can.

Step-by-step explanation:

12 < 5+8

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3 years ago

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astra-53 [7]

Answer:

ABC is similar to DEF

ABC is similar to DFE

Step-by-step explanation:

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3 years ago

PLEASE HELP WILL MARK BRAINLIEST Write the equation of the line parallel to the given line and passing through the given point.

Naily [24]

The parallel lines have the same slope.

The slope-intercept form: y = mx + b

m - a slope.

We have 6x + y = 4 |subtract 6x from both sides

y = -6x + 4 → m = -6.

The slope-point form:

$y-y_1=m(x-x_1)$

We have m = -6 and (-2, 3).

Substitute:

$y-3=-6(x-(-2))\\\\y-3=-6(x+2)\\\\y-3=(-6)(x)+(-6)(2)\\\\y-3=-6x-12\qquad|+3\\\\y=-6x-9\qquad|+6x\\\\6x+y=-9$

<h3>Answer: 6x + y = -9.</h3>

5 0

3 years ago

Hernando ate StartFraction 2 Over 8 EndFraction of a pizza for a dinner. He gave his 6 friends the rest of the pizza and told th

ozzi

Answer:

Yes, they are correct. Hernando divided 6 by 6.

Step-by-step explanation:

Given that:

Hernando ate 2/8 of a pizza for dinner.

Let the pizza be x. Then:

Hernando ate $\dfrac{2}{8} \ \ o f \ \ x$

Then he gave the rest of the pizza to his friends

Hernando now carried out the following calculations to support his activities;

$\dfrac{6}{8} \div 6= \dfrac{6 \div 6}{8}= \dfrac{1}{8}$

$\dfrac{6}{8} \times \dfrac{1}{6}= \dfrac{6 \div 6}{8}= \dfrac{1}{8}$

From the above calculation; we will see that Hernando divided 6 by 6 in both cases to get $\dfrac{1}{8}$ .

Thus, the correct answer is:

Yes, they are correct. Hernando divided 6 by 6.

3 0

2 years ago

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RES<br> Find (fºg)(1)<br> Ax) = x2 - 1<br> g(x)= v<br> a 0<br> c. 4.<br> b.<br> d. 18<br> Help pls

slava [35]

Answer:

Step-by-step explanation:

So we have the two functions:

$f(x)=x^2-1\\g(x)=\sqrt x$

And we want to find:

$(f\circ g)(1)$

This is the same as:

$f(g(1))$

So, to find the answer, find g(1) first:

$g(x)=\sqrt x\\g(1)=\sqrt1\\g(1)=1$

Now, substitute this value for g(1):

$f(g(1))\\=f(1)$

And plug this into f(x):

$f(x)=x^2-1\\f(1)=(1)^2-1\\f(1)=1-1=0$

Therefore:

$f(1)=f(g(1))=(f\circ g)(1)=0$

Our answer is A

3 0

3 years ago

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