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rjkz [21]
3 years ago
12

If your not busy mind helping me on this ​

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0

Answer:

F

Step-by-step explanation:

add all the numbers and divide them by how many numbers there is(in this case 15) to find the average of the prices

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What is greater 4/9 or 1/2?
leonid [27]
Since 4/9 in decimal form is 0.44444
and 1/2 in decimal form is 0.5

0.4444<0.5
1/2 is greater than 4/9

Hope this helped!
8 0
3 years ago
Read 2 more answers
A​ half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of​
Ainat [17]

Answer:

99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of​ today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of​ today's women in their 20's have been taken.

<u><em /></u>

<u><em>Let </em></u>\bar X<u><em> = sample mean heights</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean height of women = 64.7 inches

            \sigma = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches is given by = P(\bar X \geq 65.86 inches)

  P(\bar X \geq 65.86 inches) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } } ) = P(Z \geq -2.57) = P(Z \leq 2.57)

                                                                        = <u>0.99492  or  99.5%</u>

<em>The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.</em>

<em />

Therefore, 99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

3 0
3 years ago
What is (2x^2+6x-3) added to (2x^3-3x+2)?
Bas_tet [7]
2x² + 6x - 3 + 2x³ - 3x + 2

Combine like terms

2x³ + 2x² + 6x - 3x - 3 + 2

Final answer:
2x³ + 2x² + 3x - 1
8 0
3 years ago
Read 2 more answers
I need help creating a real world problem
marshall27 [118]
Jasmine goes to McDonalds to order food. A big mac costs $5 and large fries cost $3. If Jasmine was to buy one big mac with one batch of large fries, how much would she pay in total if a taxes of $10 was added on.

Answer: 5+3=8
8+10=18

The answer is $18 dollars.
7 0
3 years ago
Figure ABCD - Figure EFGH
Colt1911 [192]
<h3><u>Answer:</u></h3>
  • 30.5 units
<h3><u>Step-by-step explanation:</u></h3>

We know that:

  • <u>Trapezoid ABCD has one side that is 25 unit. </u>
  • <u>The other 3 sides (AB, BC, and CD) are 12 units. </u>
  • <u>EF = 6 units</u>
  • <u>EH = 12.5</u>
  • <u>Trapezoid ABCD is congruent to Trapezoid EFGH</u>

<em>If the 3 sides of the trapezoid ABCD are the same sides, then side EF, FG, GH must be of the same length because of congruence. The value of FG and GH must be the same length as EF. We can clearly see in the picture that EF is 6 units. Hence, EF is 6 units, FG is 6 units, and GH is 6 units. The work of the perimeter is shown below.</em>

<u>Work</u>

  • => 6(3) + 12.5
  • => 18 + 12.5
  • => <u>30.5 units</u>

Hence, the perimeter of EFGH is 30.5 units.

BrainiacUser1357

4 0
2 years ago
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