The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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Answer:
Distributive Property of Multiplication
False ssssssssssssssssssssssssssssssssssssssssssssss
The wall pushes back with an equal and opposite force. So it pushes with a force of 36N in the opposite direction of the push. This allows you to move away from the wall.
Answer:
A set of prime number between 5 and 15.
Listing method:{ 7,11,13}
Set builder method:{X:X is a set of prime number between 5 and 15}
In listing method,the elements are listed inside the brackets.Listing method are also called rooster method.
In set builder method,the elements are represented by a variable stating their common properties.Set builder method are also called rule method.
Hope this helps...
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