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2 years ago

14

What are the coordinates of (2,3) after a translation of 2 units left and then a rotation of 90 in a counterclockwise rotation a

bout the origin?

1 answer:

eimsori [14]2 years ago

3 0

2 units left would make it be 0,3 and a rotation of 90 degrees counterclockwise about the origin would make it -3,0

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Select the gcf of these numbers. 25 · 5· 11 and 23· 52 · 7 a 2^2 · 3

White raven [17]

The greatest common factor of the numbers is that which is the fused factors of all the numbers without the repetition of the common factors present in the given.
25·5·11 = 5·5·5·11
23·52·7 =23·2·2·13·7
Since, there are no repeated factors, the answer would be,
5·5·5·11·23·2·2·13·7
The answer unfortunately is not among the choices.

7 0

3 years ago

You haft too use elimination to solve this thank you

lakkis [162]

Answer:

x=0, y=-2

Step-by-step explanation:

Because 9y appears twice in both equations, you can subtract the equations to eliminate the y variable so you can solve for x:

-7x + 9y = -18

-(4x + 9y = -18)

__________

-11x = 0

x = 0

Since we know x=0, then we plug it back into one of the equations to get the value of y:

-7x + 9y = -18

-7(0) + 9y = -18

0 + 9y = -18

9y = -18

y = -2

Therefore, x=0, and y=-2

5 0

3 years ago

Four friends went fishing and each caught one fish. The fish they caught weighed 1 3/8 lb, 1 5/16 lb, 1 7/10 lb, and 1 3/5 lb. W

Anna71 [15]

The correct answer is 17/10.

8 0

2 years ago

Read 2 more answers

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

2 years ago

ANSWER PLZ QUICK AND FAST

kherson [118]

Half of n, is option D, n/2.

This is because if you divide something by 2, you are dividing it in half.

Hope this helps!

3 0

3 years ago