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3 years ago

7

I REALLY NEED HELP! △DLZ∼△MYR What is YR? (Picture Included!)

1 answer:

o-na [289]3 years ago

6 0

Answer:

YR = 33.6 in.

Step-by-step explanation:

△DLZ∼△MYR

LZ / DZ = YR / MR

21/18 = YR / 28.8

7 / 6 = YR / 28.8

YR = 7 * 28.8 / 6

YR = 33.6

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Problem PageQuestion The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate paramet

asambeis [7]

Answer:

<em>t = 1.51</em>

Step-by-step explanation:

<u>Exponential Model</u>

The exponential model is often used to simulate the behavior of a magnitude that either grow or decay in proportion to the existing amount of that magnitude.

The model can be expressed as

$M=M_oe^{kt}$

In this case, Mo is the initial mass of the radioactive substance and k is a constant which value is positive if the mass is growing or negative if the mass is decaying.

The value of k is not precisely given in the question, we are assuming $k=-0.2$

The model is now

$M=M_oe^{-0.2t}$

We are required to compute the time it takes the mass to reach one-half of its initial value:

$\displaystyle \frac{M_o}{2}=M_oe^{-0.2t}$

Simplifying

$\displaystyle \frac{1}{2}=e^{-0.2t}$

Taking logarithms

$\displaystyle ln\frac{1}{2}=ln(e^{-0.2t})=-0.2t$

Solving for t

$\displaystyle t=-\frac{ln\frac{1}{2}}{0.2}=1.51$

6 0

3 years ago

Someone please help!

Luda [366]

g (f(-3)) = -6 is your answer

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3 years ago

An aptitude test is designed to measure leadership abilities of the test subjects. Suppose that the scores on the test are norma

Komok [63]

Using the normal distribution, it is found that 0.0329 = 3.29% of the population are considered to be potential leaders.

In a <em>normal distribution</em> with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 550, hence $\mu = 550$ .

The standard deviation is of 125, hence $\sigma = 125$ .

The proportion of the population considered to be potential leaders is <u>1 subtracted by the p-value of Z when X = 780</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{780 - 550}{125}$

$Z = 1.84$

$Z = 1.84$ has a p-value of 0.9671.

1 - 0.9671 = 0.0329

0.0329 = 3.29% of the population are considered to be potential leaders.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

8 0

2 years ago

Maria and Katy have string Maria's is 6 cm longer that Katy's. When they put both of the strings together the total is 84 How lo

butalik [34]

Answer:

Maria's string is 45 cm long and Katy's string is 39 cm long

Step-by-step explanation:

Let's call the size of Maria's string X, and the size of Katy's string Y.

So, using the information from the problem, we can formulate a system of equations:

If Maria's string is 6 cm longer than Katy's, so:

X = Y + 6

If the strings together have 84 cm, so:

X + Y = 84

The first equation can be rewritten as X - Y = 6

Summing up both equation, we have that:

2X = 90

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Using X value in the first equation, we have that:

45 = Y + 6

Y = 39

So, Maria's string is 45 cm long and Katy's string is 39 cm long

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3 years ago

2-9 of the students are in a school are in 6th grade how many sixth graders are there if the school has 27 students

Elden [556K]

Answer:

Step-by-step explanation:

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2 years ago