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n200080 [17]
3 years ago
10

15 POINT, need this answered ASAP

Mathematics
1 answer:
ioda3 years ago
7 0

Option A

The equation of ellipse in standard form is \frac{x^{2}}{9}+\frac{y^{2}}{4}=1

<u>Solution:</u>

Given, We have to write an equation of an ellipse in standard form with the center at the origin

Given that vertex at (-3,0) and co-vertex (0,2)

The standard form of an ellipse is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

where a is x- intercept and b is y – intercept.

We have vertex (-3, 0) and (0, 2) from these we can say that, x – intercept is – 3 and y – intercept is 2 . As we know that intercepts are the respective values when other variables becomes 0.

Now, let us find our ellipse equation:

\begin{array}{l}{\rightarrow \frac{x^{2}}{(-3)^{2}}+\frac{y^{2}}{2^{2}}=1} \\\\ {\rightarrow \frac{x^{2}}{9}+\frac{y^{2}}{4}=1}\end{array}

Hence, the standard form equation is \frac{x^{2}}{9}+\frac{y^{2}}{4}=1

Thus option A is correct

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