A pet store has 9 dogs, 6 cats, 8 gerbils, and 7 parrots. A pet is chosen at random. What is the probability of choosing a cat o
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Using the t-distribution, it is found that the p-value of the test is 0.007.
At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:
At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:
.
We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:
The parameters are:
is the sample mean.
is the value tested at the null hypothesis.
- s is the standard deviation of the sample.
- n is the sample size.
For this problem:
Then, the value of the test statistic is:
We have a right-tailed test(test if the mean is greater than a value), with <u>t = 2.69</u> and 23 - 1 = <u>22 df.</u>
Using a t-distribution calculator, the p-value of the test is of 0.007.
A similar problem is given at brainly.com/question/13873630
1.) Start by figuring out what the 4x3 grid would look like. In this grid, we have 12 boxes (4 x 3 = 12).
2.) Now let's calculate 25% of 12. When changing a percent to a decimal, simply move the decimal point over to the left two places. So then 25% = .25 when written as a decimal. Multiply 25 x 12. 25% of 12 equals 3.
3.) Now your grid would have 3 boxes shaded in. I put two examples of this in the attached image. However, your boxes can be shaded in anywhere in the grid, as long as only 3 of them are shaded in!
2.) Now let's calculate 25% of 12. When changing a percent to a decimal, simply move the decimal point over to the left two places. So then 25% = .25 when written as a decimal. Multiply 25 x 12. 25% of 12 equals 3.
3.) Now your grid would have 3 boxes shaded in. I put two examples of this in the attached image. However, your boxes can be shaded in anywhere in the grid, as long as only 3 of them are shaded in!