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2 years ago

Which statement is NOT true about the slope of a straight-line graph?

Mathematics

2 answers:

Lorico [155]2 years ago

8 0

Answer:

Slope is 1

if the line is vertical.

Step-by-step explanation:

soldi70 [24.7K]2 years ago

5 0

Answer:

Option D. Slope is 1 if the line is vertical

Step-by-step explanation:

we have

Part A) Slope is a measure of the steepness of the line

The statement is true

Because, the steepness of a line is measured by the absolute value of the slope.

Part B) Slope is the ratio of vertical change to horizontal change

The statement is true

Because the formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Is the ratio of vertical change to horizontal change

Part C) Slope is zero if the line is horizontal

The statement is true

Because If the line is horizontal, the y-coordinate of two points is the same

therefore

The vertical change is equal to zero

Part D) Slope is 1 if the line is vertical

The statement is Not true

Because, if the line is vertical the slope is undefined

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Lynn has a box of crayons.

Scrat [10]

Answer:

<em>There are 72 crayons in the box</em>

Step-by-step explanation:

<u>Fractions</u>

To solve this problem we'll manage numbers as fractions to keep the precision up to the end of it.

Lynn has a box of crayons. It's given 4/9 of the crayons are blue. The remaining crayons are:

$1-\frac{4}{9}=\frac{5}{9}$

From that portion, 65% are red, or equivalently, 35% are yellow.

We write 35% as a fraction:

$\displaystyle 35\%=\frac{35}{100}=\frac{7}{20}$

Thus, the portion of yellow crayons is:

$\displaystyle \frac{7}{20}\cdot \frac{5}{9}=\frac{7}{36}$

This fraction of x crayons is equal to 14, thus:

$\displaystyle x=\frac{14}{\frac{7}{36}}=14\cdot\frac{36}{7}$

x = 72

There are 72 crayons in the box

7 0

2 years ago

Just solve the question :)

VashaNatasha [74]

Answer:

775

Step-by-step explanation:

Hello :3

750 + 25 = 775.

8 0

2 years ago

Use the graph to find the x-intercept for the equation ý +2 Graph: Y + 2 = 2(x+3)

alex41 [277]

Answer:

(-2, 0)

Step-by-step explanation:

8 0

2 years ago

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((5^(3))^(5))/(5^(7))

Norma-Jean [14]

Answer:

Step-by-step explanation:

equals 48 trust me ive had that question

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2 years ago

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A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a

Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 = 0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = $2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750$

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

$W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5$

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0

2 years ago