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mr Goodwill [35]
3 years ago
9

An empty erlenmeyer flask that weighs 245.8 g is filled with 125 mL of carbon tetrachloride . The weight of the flask and carbon

tetrachloride is found to be 444.6 g. From this information , calculate the density of carbon tetrachloride .​

Mathematics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

The density is 1.59 g/mL. Therefore, the substance will NOT float in water.

Step-by-step explanation:

The following data were obtained from the question:

Mass of empty flask = 245.8 g

Mass of flask + CCl₄ = 444.6 g

Volume of CCl₄ = 125 mL

Density of CCl₄ =?

Next, we shall determine the mass of carbon tetrachloride, CCl₄. This can be obtained as follow:

Mass of empty flask = 245.8 g

Mass of flask + CCl₄ = 444.6 g

Mass of CCl₄ =.?

Mass of CCl₄ = (Mass of flask + CCl₄) – (Mass of empty flask)

Mass of CCl₄ = 444.6 – 245.8

Mass of CCl₄ = 198.8 g

Finally, we shall determine the density of carbon tetrachloride, CCl₄ as follow:

Mass of CCl₄ = 198.8 g

Volume of CCl₄ = 125 mL

Density of CCl₄ =?

Density = mass / volume

Density of CCl₄ = 198.8 / 125

Density of CCl₄ = 1.59 g/mL

The density of water is 1 g/mL. Since the density of carbon tetrachloride, CCl₄ (i.e 1.59 g/mL) is bigger than that of water, the substance will not float in water.

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m_a_m_a [10]

Answer:

4.2 x 10⁶

Step-by-step explanation:

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To do this, first you multiply the coefficients:

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So the result would be:

42 x 10⁵

However the following the form of scientific notation, you need to move the decimal one more time so that means you add one more to the exponent of 10.

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3 years ago
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Andrej [43]

Answer:

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Step-by-step explanation:

The total area of the box is the sum of the areas of all faces of the box. The top, bottom, front, and back faces are rectangles 18 in long. The end faces each consist of a rectangle and a triangle. We can compute the sum of these like this:

The areas of top, bottom, front, and back add up to be 18 inches wide by the length that is the perimeter of the end: 2·5in +2·8 in + 9.6 in = 35.8 in. That lateral area is ...

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The area of the triangle on each end is equivalent to the area of a rectangle half as high, so we can compute the area of each end as ...

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Then the total area is the lateral area plus the area of the two ends:

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inessss [21]

Answer:

a) 3n^2 + 11n + 8

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Step-by-step explanation:

10) 3(10^2)+ 5*10 = 350

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hoa [83]

Answer:

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Step-by-step explanation:

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dA = 2π * 24 * 0.2

dA = 9.60πcm²

3 0
2 years ago
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