Answer:
Given in figure ABCD:
∠ABD≅∠CBD
AB≅CB
To prove:
∠A≅∠C
Solution:
In the figure ABCD, we will first prove the Δ ABD and Δ CBD are congruent.
Thus the proof can be given as:
Statement Reason
1) Given
2) Given
3) Reflexive property of congruence (As the segment is congruent to itself)
4) S.A.S (Side Angle side)
5) Corresponding parts of congruent triangles are congruent.
Hence proved.
Answer:
Step-by-step explanation:
for two lines to be parallel they MUST have the same slope but have different Y intercepts ( Y axis crossing values)
parallel lines will never intersect each other
first I use a graphing calcuator to solve the problem
I like to use y intercept form better, but you don't have use it
I will try to solve it directly without going through the y intercept equation
x + 5y = 10 in y intercept form y = mx + b is
5y = -x + 10 divide both sides by 5
y = -x/5 + 10/5
y = -x/5 + 2
Now I need to find a parallel line that passes through the x =1 and y = 3 point recall this line will have the same slope = m = -1/5
and a different Y axis crossing point 'b' that we don't know
y = -x/5 + b y = 3 when x = 1 so slove for 'b'
3 = -1/5 + b
3 = -0.2 + b add -0.2 to both sides
3.2 = b
y = -x/5 + 3.2 this is answer in y intercept form
if you multiply both sides by 5
5y = -x + 16 add x to both sides
x + 5y = 16 answer in standard form
THE EASIER WAY TO SOLVE THE PROBLEM IS ......
x + 5y = 10 find a line parallel that passes through x = 1, y = 3
x + 5y = Z Z is an unknown value plug in x and y and solve for Z
1 + 5(3) = Z
Z = 16 so the parallel line in standard form is
x + 5y = 16
same as before, my y intercept method was correct, but not worth the effort
