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Mkey [24]
3 years ago
13

3/4•3/4???? I can’t do it in my head and I don’t know how to make a decimal into a fraction

Mathematics
2 answers:
Monica [59]3 years ago
4 0

Answer:

0.5625

Step-by-step explanation:

3/4 as a decimal is 0.75

0.75×0.75=0.5625

oksano4ka [1.4K]3 years ago
4 0

Answer:

0.75 x 0.75 = 0.5625

Step-by-step explanation:

3/4=.75

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What is the reason for each step in the solution of the equation <br> 12-5x+6x=4
zhannawk [14.2K]

Answer: x=-8

Step-by-step explanation: 12-5x+6x=4                                                                 1. Combine like terms: -5x+6x+12=4                                                                       2. Simplify: x+12-12=4-12                                                                                         3. Subtract 4 from -12 so that you can find out what x is: x=-8

7 0
3 years ago
-2+n=-8(1-8n)+6 solve for n.
blsea [12.9K]

-2 + n = -8(1 - 8n) + 6

Distribute the -8

-2 + n = -8 + 64n + 6

Combine like terms.

-2 + n = 64n - 2

Add 2 to both sides and subtract n from both sides.

0 = 63n

Divide both sides by 63

0 = n

7 0
3 years ago
Helpppp!!!!!!!!!!!!!!
ratelena [41]

Answer:

3075

Step-by-step explanation:

3 0
3 years ago
Drag a reason to each box to complete the proof.
Anna [14]

To start off with, DF=EG's reason is given, since you stated it was given.


Next, DE+EF = EF+FG's reason is because of the substitution property of equality. Think "if a = c, b = c, then a = b"


Lastly, DE = FG's reason is because of the Subtraction property of equality. If you subtract EF on one side, you must do it on the other side.

6 0
3 years ago
Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

8 0
3 years ago
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