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valentina_108 [34]
3 years ago
9

Recent study of alcohol drinking practices among college students found that the average number of drinks per week consumed was

3.5 with a standard deviation of 2.0. Suppose you examined the number of drinks per week consumed by a large sample of students from the population. Which of the following statements is true? (Assume the distribution of number of drinks per week is unimodal). A.) Distribution is right skewed
B.) Distribution is left skewed

C.) The normal normal model would be a good description of these data

D.) About 2.5% of students in our sample would drink more than 7.5 per drinks per week
Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Here as we can see that minimum drink a person can drink is 0 and is

(3.5-0)/2 =1.75 std deviation away from mean

which reflects that distribution;s right tail is more extended

therefore option A is correct: Distribution is right skewed

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Oliga [24]

Answer:

Option A. -6.5

Step-by-step explanation:

we have

6.4r-5.9r=-3.25

Solve for r

That means ---> isolate the variable r

Combine like terns left side of the equation

0.5r=-3.25

Divide by 0.5 both sides

0.5r/0.5=-3.25/0.5

r=-6.5

4 0
3 years ago
6. Five years ago, Ross was N times as old as
Tema [17]

Answer:

14N+5

Step-by-step explanation:

Five years ago; Rose Nx

Amanda x

Now; Rose Nx+5

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8 0
2 years ago
Brandon discovered that his daily routine of buying a slice of pizza and a soda at lunch was costing him more than 18,000​$ per
Minchanka [31]

Answer:

This statement makes sense because this would mean that a slice of pizza and a soda costs him about ​$49 a day

Step-by-step explanation:

Given

The total spent on a slice of pizza and a soda is:

Cost > \$18000 per year

Required

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First, we calculate the daily amount spent on a slice of pizza and a soda.

Assume that the yearly cost is: $18000

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This means that he spends about $49 daily

5 0
3 years ago
On a lunch counter, there are 3 oranges, 5 apples, and 2 bananas. If 3 pieces of fruit are selected, find the probability that 1
muminat

Answer:

Probability = \frac{1}{24}

Step-by-step explanation:

Given

Oranges = 3

Apples = 5

Banana = 2

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Required

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Probability = \frac{3}{10} * \frac{5}{9} * \frac{2}{8}

<em>The difference in the numerator is as a result of picking the fruit without replacement</em>

Probability = \frac{30}{720}

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3 years ago
12.125 rounded to the nearest tenth.
nika2105 [10]
Answer: 12.1
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8 0
3 years ago
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