Here's the given:
P=$400
i=7.5%
A=$8500
The formula used for this problem is:
A = P(1+i)^t
Manipulating the equation to arrive at t, we have:
t = ln(A/P) / ln(1+i)
Plugging in values:
t = ln($8500/$400) / ln(1+0.075)
<span>t = 42.26 years</span>
Answer:
SSS or D on edge
Step-by-step explanation:
just took the test
2+52=54
2+72=74 HOPE THIS HELPS :)
Subtract 1/4 x because you wanna isolate y
Answer:
The depreciation each year is option B. $1500.00
Step-by-step explanation:
Initial value of car = $9600
Salvage value = $600
Salvage value is the final value of product after all the depreciation have been applied on the product.
So, total depreciation on the car = 
Also, it is given that the depreciation occurs at a straight line method i.e. same depreciation occurs every year.
Depreciation in 6 years = $9000
Depreciation in 1 year =

Hence, option B. $1500 is the correct answer for the depreciation every year.