Answer: yes, it is
Step-by-step explanation:
A number is divisible by 6 if it is divisible by 2 and 3 simultaniously.
n = k(k+1)(k-1)
If k-1 is a multiple of 3, n is divisible by 3, so one of the requirements is ok.
Now, if k-1 is a multiple of 3, it can be even or odd.
if k-1 is even, then it is divisible by 2 and as it is divisible by 3 as well, n is divisible by 6
if k-1 is odd, then k and k+1 is even, hence, divisible by 2.
As n = k(k+1)(k-1), n is also divisible by 6.
Answer:
The formula for Pascal's Triangle comes from a relationship that you yourself might be able to see in the coefficients below.
(x + y)0 (x + y)1 (x + y)² (x + y)3 (x + y)41 x + y x² + 2xy + y² x3 + 3x2Y + 3xY2 + y3 x4 + 4x3Y + 6x2Y2 + 4XY3 + Y4
HOPE THIS HELPS!
Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
5*9=45
1*9=9
Then add both numbers together
45+9=54
Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6
