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Firdavs [7]
2 years ago
7

When b = 3 and c = 4, b⁵c⁶/b³c³​

Mathematics
2 answers:
Vladimir [108]2 years ago
7 0

Substitute the variables for the numbers. Then solve.

b⁵ = 3⁵ = 243

c⁶ = 4⁶ = 4096

b³ = 3³ = 27

c³ = 4³ = 64

(243)(4096)/(27)(64) = 576

Nimfa-mama [501]2 years ago
6 0

Answer:

simplify the powers, so b^(5-3) * c^(6-3) =

b^2 * c^3 = 3^2 * 4^3 =

9 * 64 = 576

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What are the verter and x-intercepts of the graph of the function given below?<br> y=x2-2x-35
horsena [70]

For x intercepts, plug in 0 for y.

               0 = (x^2) - 2x - 35

*factoring* = (x-7)(x+5)

x intercepts = 7,-5

As for the vertex, you can use the equation -b/2a for the x-coordinate of the vertex

so,

x = -b/2a = -(-2)/2 = 1

then just find the y value by plugging it back in to the equation.

y = ((1)^2) - 2(1) - 35

= -36

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5 0
3 years ago
86.40-12.59 plz answer
Evgen [1.6K]
The answer is 73.81 :))
8 0
3 years ago
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PLEASE HELP ILL GIVE BRAINLIEST
DanielleElmas [232]

Option A:

(x-5)^{2}+(y-3)^{2}=16

Solution:

Given data:

Center of the circle is (5, 3).

Radius of the circle = 4

To find the equation of the circle:

The general form of the equation of a circle in centre-radius format is

(x-h)^{2}+(y-k)^{2}=r^{2}

where (h, k) is the centre of the circle and r is the radius of the circle.

Substitute the given values in the equation of a circle formula:

(x-5)^{2}+(y-3)^{2}=4^{2}

(x-5)^{2}+(y-3)^{2}=16

The equation of the given circle is (x-5)^{2}+(y-3)^{2}=16.

Hence Option A is the correct answer.

5 0
3 years ago
Which of the following points lie in the solution set to the following system of inequalities? y &gt; −3x + 3 y &gt; x + 2
OverLord2011 [107]

Answer:

y> -3x

3

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5 0
3 years ago
Can someone help me with this math homework please!
Zepler [3.9K]

Answer:

Step-by-step explanation:

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To eliminate the fraction, each term should be multiplied by 4

ANS:option c

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0.05 +0.1y = 0.12+0.06y

Ans : Option c

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Add 'b' to both sides

4b + b + 6 = 2 + 4

5b + 6 = 6

Subtract 6 from both sides

5b = 6 - 6

5b = 0

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Ans : Option b

4) Maximum decimal places in this equation is 2. So, to eliminate decimal places, The equation should be multiplied by 100

Ans: option d

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Add 3y to both the sides

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Subtract 6 from both sides

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Divide bothe sides by 4

y = 20/4

y = 5

Ans: option c

6) '2x' is  subtracted from both side of the equation.

Ans: option a - subtraction property of equality

                     

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