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Firdavs [7]
2 years ago
7

When b = 3 and c = 4, b⁵c⁶/b³c³​

Mathematics
2 answers:
Vladimir [108]2 years ago
7 0

Substitute the variables for the numbers. Then solve.

b⁵ = 3⁵ = 243

c⁶ = 4⁶ = 4096

b³ = 3³ = 27

c³ = 4³ = 64

(243)(4096)/(27)(64) = 576

Nimfa-mama [501]2 years ago
6 0

Answer:

simplify the powers, so b^(5-3) * c^(6-3) =

b^2 * c^3 = 3^2 * 4^3 =

9 * 64 = 576

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MaRussiya [10]
I might be wrong but 9

9*2=18
18+7= 25
25 square root = 5

Answer is 9
7 0
3 years ago
Someone help me with this math
Makovka662 [10]

dont know wish i could help you :(  sorry i hate when i can't answer a question it makes me feel bad

5 0
3 years ago
Find the x- and y- intercepts of parabola y=5x^2-16x+10
____ [38]

Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\

The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
2 years ago
A card is picked at random from a deck of cards, after putting it back another card is picked at random. ​Are these two events d
kvv77 [185]

Answer: Independent event

Step-by-step explanation:

When two events are independent of each other, this means that the probability that one event will occurs does not in any way affects the probability of the occurrence of the other event.

For example, card is picked at random from a deck of cards, and after putting it back,thne another card is picked at random. ​The probability of picking the cards is not affected by each other since it is put back.

6 0
3 years ago
Translate each sentence into an equation
Mazyrski [523]

Answer:

1. X/2 = 4

2. 3x - 2 = 11

3. 2x - 5 = 15

4. 2x-1=12

5. 9x = 2(x+5)

Step-by-step explanation:

8 0
3 years ago
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