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2 years ago

Convert 7.2 ⋅ 10−3 to standard form. (3 points) need help ASAP

Mathematics

1 answer:

zhenek [66]2 years ago

3 0

Answer:

7.2x10^-3--->.0072

Step-by-step explanation:

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A customer calls and has questions about the bill for their first month's subscription. They want to know why the monthly rate i

HACTEHA [7]

Answer:

The subscription began about 10 days before the 15th of the month.

Step-by-step explanation:

The correct option is:

The subscription began about 10 days before the 15th of the month.

The reason for being charged $60 instead of $45 which is the monthly rate is that they started the subscription prior the the cycle date of the bill period. Due to the change in the cycle date, the customer is getting a prorated charge for the days that had service prior to the date of the bill and current cycle starting

3 0

2 years ago

Find the accumulated value of an investment of $14,000 at 10% compounded semiannually for 11 year

kifflom [539]

Given:

Principal = $14000

Rate of interest = 10% compounded semiannually.

Time = 11 years.

To find:

The accumulated value of the given investment.

Solution:

Formula for amount or accumulated value after compound interest is:

$A=P\left(1+\dfrac{r}{n}\right)^{nt}$

Where, P is the principal values, r is the rate of interest in decimal, n is the number of times interest compounded in an year and t is the number of years.

Compounded semiannually means interest compounded 2 times in an years.

Putting $P=14000,r=0.10,n=2,t=11$ in the above formula, we get

$A=14000\left(1+\dfrac{0.10}{2}\right)^{2(11)}$

$A=14000\left(1+0.05\right)^{22}$

$A=14000\left(1.05\right)^{22}$

$A\approx 40953.65$

Therefore, the accumulated value of the given investment is $40953.65.

8 0

2 years ago

Read 2 more answers

Integrate t sec^2 (2t) dt

Neporo4naja [7]

F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt

As integral of tan u = - ln (cos (u)), you get :

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer

8 0

3 years ago

Read 2 more answers

Jeffery thinks that the largest place value 8.21 and 19.5 have in common is the tens place. Austin thinks that the largest place

katovenus [111]

The answer is A. jeffery

4 0

2 years ago

Which statement is true about the domain of y = 3(2^-x)? Explain.

SVEN [57.7K]

We want to determine the domain of ${y=3 \cdot 2^{-x}=3 \cdot ({2^{-1}})^x=3 \cdot ({ \frac{1}{2}})^x$

any function of the form $y=f(x)=a \cdot b^x$ is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.

The domain of such functions is all real numbers.

That is for any x, the expression <span>3(2^-x) "makes sense".

Answer: </span><span>The domain is all real numbers</span>

8 0

2 years ago