Answer:
a.the length of midsegment of an equilateral triangle with side lengths of 12.5 cm.=12.5/2=6.25cm
b.
sinceUT is the perpendicular bisector of line segment AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x.
than AT=BT
3x+6=42-x
3x+x=42-6
x=36/4=9
AT=3×9+6=27+6=33
c.
since angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.
EH=GH
5y+10=28-y
6y=28-10
y=18/6=3
Answer:
75.00
Step-by-step explanation:
1500*0.05
because 5% is her interest you convert 5% into a decimal = 0.05
then you multiply 1500 by 0.05 and you get 75.00
Answer:
My solution is I don't have solutions
Answer:
16
Step-by-step explanation:
4+8/2*(6-3) = 4+8/2*3 = 4+4*3 = 4+12 =16
