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marshall27 [118]
3 years ago
14

Four thousand students at a school were asked to name their favorite pizza topping. The results were 800 Pepperoni, 1,000 Sausag

e, 1,200 Mushrooms, 560 Peppers, 240 Onions, and 200 Other. Your friend expresses these results in this circle graph. Your friend made a mistake, however. What is wrong with his graph?

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:

The mistake my friend made was that pepperoni and peppers are mixed up, pepperoni is suppose to be 20% while peppers is supposed to be 14%

Step-by-step explanation:

Given that 4000 students

Pepperoni = 800

Sausage = 1,000

Mushrooms = 1,200

Peppers = 560

Onions = 240

Other = 200

To find the degree of each on the circle graph, we have:

Pepperoni = 800/4,000 * 100 = 20%

Sausage = 1,000/4,000 * 100 = 25%

Mushrooms = 1,200/4,000 * 100 = 30%

Peppers = 560/4,000 * 100 = 14%

Onions = 240/4,000 * 100 = 6%

Other = 200/4,000 * 100 = 5%

The mistake my friend made is that pepperoni and peppers are mixed up, pepperoni is suppose to be 20% while peppers is supposed to be 14%

4vir4ik [10]3 years ago
3 0

Answer:

The pepperoni and peppers are mixed up

Step-by-step explanation:

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how many 3 element subsets of {1, 2, 3, 4, 5, 6, 7, 8, ,9, 10, 11} are there for which the sum of the elements in the subset is
AURORKA [14]

Answer:

There are 155 ways in which these elements casn occur.

Step-by-step explanation:

We want 3 element subsets whose sum are multiples of 3

1+2+3= 6

1+2+6= 9

1+2+9= 12

1+9+11=21

1+3+5=9

1+4+8=12

1+5+6=12

1+6+8=15

1+7+10=18

1+8+9=18

1+9+11=21

2+3+7=12

2+4+6=12

2+4+9=15

2+5+11=18

2+6+7=15

2+7+9=18

2+8+5=15

2+8+11=21

2+9+10=21

3+6+9= 18

3+9+11=21

3+10+11=24

6+9+10=27

6+8+11=27

6+7+11=24

7+8+9= 24

8+9+10=27

7+9+11=27 .........

We have 11 elements

We need a combination of 3

The combinations can be in the form

even+ even+ odd

odd+odd+odd

even + odd+odd

So there are 3 ways in which these elements can occur

Total number of combinations with  3 elements =11C3= 165

There are 6 odd numbers and 5 even numbers.

Number of subsets with 3 odd numbers = 6C3= 20

Number of two even numbers and 1 odd number = 5C2*6C1=10*6= 60

Number of 2 odd and 1 even number = 6C2* 5C1= 5*15= 75

So 20+60+75=155

There are 155 ways in which this combination can occur

6 0
3 years ago
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