The correct question is
<span>What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3
</span>
we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0
the answer is
<span>x - 3y - 7 = 0</span>
Answer:

Step-by-step explanation:
I assume that the three points given are the vertices of the triangle. So the three points are:
A (-4,1)
B (-7,5)
C (0,1)
The area of a triangle is given by:

where b is the base and h is the height.
Here we can take as follows:
- We can take the base to be the side AC, so that its length is equal to the distance between the two points:

- The height of the triangle is therefore the perpendicular distance between AC and point B. This is equivalent the difference in the x-coordinate between any point on AC and B, so:

Therefore, the area of the triangle is:

Answer:
the domain is {0, 1, 2, 3, 4... to positive infinity}
The range is {-1, -3, 0, -4 and so on}
this is not a function
Step-by-step explanation:
domain is a set of all x values, so just write the x values based on the graph
range is a set of all y values, so just write y values based on the graph
not function because it doesnt satisfy with the vertical line test.
i hop it help u
The answer is 44 h(-7)= -7^2 -5 =49-5=44