Answer:
There is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 1432
p = 23% = 0.23
Alpha, α = 0.05
Number of theft complaints , x = 321
First, we design the null and the alternate hypothesis
This is a one-tailed test.
Formula:
Putting the values, we get,
Now, we calculate the p-value from the table.
P-value = 0.298
Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.
Conclusion:
Thus, there is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.
8 can go into 71 seven times
The answer to 75 squared is 5,625.
You divide 22 by 10 (2.2) and then multiply that by 3 to get 30%, which is 6.6. Then, you divide 2.2 by 2 to get 1.1, which is 5%. After this you just add them up to get the answer as 7.7.
Also, if you have q calculator, you can do it the short way and do 22 × 0.35 = 7.7