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Mrrafil [7]
2 years ago
6

Please help me with this!!

Mathematics
2 answers:
rewona [7]2 years ago
8 0
Area = b * h
Area of orange = area of big square subtract by area of small square

Small square = b^2
Big square = a^2
(a^2 - b^2) = (a - b)( a + b)

Solution: (a - b) (a + b)
melomori [17]2 years ago
5 0

Answer:

a² - b² = (a + b)(a - b)

Step-by-step explanation:

The side of the outer square is a. Its area is a².

The side of the inner square is b. Its area is b².

The area of the orange section is the difference of the area of the two squares.

A = a² - b²

The area is the difference of two squares which factors into the product of a sum and a difference.

Factor the area:

a² - b² = (a + b)(a - b)

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writing an equation of a line given its slope and y-intercept. write an equation in slope-intercept form for the line with slope
Gre4nikov [31]

Answer:

y = -5(x-1)

Step-by-step explanation:

A y-intercept of 1 means that the point (0,1) falls on the line.

Slope-intercept form is y-y_{1} =m(x-x_{1} ) where m is the slope...

Therefore, the slope-intercept equation is y-1=-5(x-0) or y-1=-5x

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3 years ago
I need help finding m
Romashka-Z-Leto [24]

Answer:

i need this too hahahaha

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2 years ago
What is the measure of angle x?
vfiekz [6]

See the attached picture:

4 0
3 years ago
Read 2 more answers
Jennifer has a taco stand.she found that her daily costs can be modeled by C(x)=x^2-40x+610. if she wants to keep her daily cost
Svetllana [295]
Plug in 300 for C(x), to get:
300=x^{2} -40x=610
Then subtract to get: 0=0= x^{2} -40x+310
Then use the quadratic formula and plug everything in. Use a calculator to simplify.

You'll get two answers: 29.486 and -0.513.
Since you can't sell <em>"negative" </em>tacos, use the positive solution
Around 29-30 tacos.
8 0
3 years ago
How do you do...<br> cos2x-sin2x=1-2sin2x
Bess [88]
sin (2 \alpha) =2\cdot sin  \alpha \cdot cos  \alpha \\cos(2 \alpha )=1-2sin^2  \alpha \\-------------------- \\cos2x-sin2x=1-2sin2x\\cos2x+sin2x=1\\1-2sin^2x+2sinx\cdot cosx=1\\-2sinx(sin x-cosx)=0\\ -2sinx=0\ \ \ \ or\ \ \ \ sinx-cosx=0\\\\1)\ -2sinx=0\ \ \Leftrightarrow\ \ sinx=0\ \ \Leftrightarrow\ \ x_1=k \pi \ \ and\ \ k\in I\\2)\ \ sinx-cosx=0\ \ \Leftrightarrow\ \ sinx=cosx\ /:cosx\ \ \ \ \ \wedge\ \ \ \  cos x \neq 0\\tanx=1\ \ \Leftrightarrow\ \ x_2= \frac{ \pi }{4} +k \pi \ \ and\ \ k\in I
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3 years ago
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