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SashulF [63]
4 years ago
7

Find Percent Increase or Percent Decrease

Mathematics
1 answer:
JulsSmile [24]4 years ago
6 0

Answer:

15.6%

Step-by-step explanation:

$52,000 - 45,000 = $7,000

$7,000 ÷ 45,000 = 0.15555555... ≈ 15.6%

You might be interested in
-k/3 = 9<br> answer = ??
taurus [48]

Answer:

-k=9×3

-k=27

God luck friend

7 0
3 years ago
Read 2 more answers
An envelope is 11 inches wide and measures 19 inches along the diagonal.How tall in inches is the envelope
nataly862011 [7]

Answer:

The envelop is 15.49 inches tall

Step-by-step explanation:

To find how tall the envelop is, we will follow the steps below;

We can use Pythagoras theorem formula to find the height of the envelop'

adjacent =width of the envelop= 11 inches   opposite= height (h)  of the evelope = h      and hypotenuse = diagonal of the envelop= 19 inches

Using Pythagoras theorem;

opposite² + adjacent² = hypotenuse²

h² + 11² = 19²

h² + 121 = 361

subtract 121 from both-side of the equation

h² + 121-121 = 361-121

h²  = 240

Take the square root of both-side

√h²  =√ 240

h≈15.49 inches

The envelop is 15.49 inches tall

7 0
4 years ago
While shopping at store, Billy
romanna [79]

Answer:

A. 270

Step-by-step explanation:

30% can be rewritten as 3/10

To multiply 900 by 3/10, just divide by 10 (90) and multiply by 3 (270)

Therefore, the answer is A. 270

Bonus: To find the actual price, just subtract this amount (270) from the original price (900).

The television costs $630.

3 0
3 years ago
Read 2 more answers
Solve for b.<br><br> b /–4+ 18 = 20
disa [49]

Answer:

280

Step-by-step explanation:

(b/ -4 + 18 )(-4 + 18) = 20 (-4 +18)

b = 20 (-4 + 18)

b = 20 (14)

b = 280

4 0
3 years ago
For a cone, if the radius was quadrupled and the slant height was reduced to 1/6 of its original size what would be the formula
Paladinen [302]
Let r be the radius of the cone's base and \ell the slant height.

The surface area of a cone is

A=\pi r^2+\pi r\ell

If the radius is quadrupled (r\to4r) and the slant height scaled by a factor of \dfrac16, then the new area is

A=\pi(4r)^2+\pi (4r)\left(\dfrac\ell6\right)
A=16\pi r^2+\dfrac23\pi r\ell
7 0
3 years ago
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