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3 years ago

Help would be greatly appreciated

Mathematics

1 answer:

UNO [17]3 years ago

5 0

Answer:2/pi

Step-by-step explanation:

First, name the points. Top Left will be A, Top Right will be B, Bottom Right will be C, and Bottom Left will be D. Now, the area of ABCD is 4. Then, we have to find the area of the circle. The center to the midpoint of AB is 1. The length of the midpoint of AB to B is 1. So, using the Pythagorean Theorem, it will be 1^2 + 1^2 = 2, then it will be sqrt2. Finding the area of the circle will be easy now that we have the radius. sqrt2*sqrt2*pi = 2pi. So, it will be 4/2pi, and simplified, it will be 2/pi.

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user100 [1]

The equation for a parabola with vertex $(h, k)$ is
$y=a(x-h)^{2}+k$

We plug in:
$y=a(x-4)^{2}+75$

We find $a$ by plugging in the point $(0, 27)$ :
$27=a(0-4)^{2}+75$
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$\Rightarrow a=-3$

So our equation is
$y=-3(x-4)^{2}+75$

To find x-intercepts, we set $y=0$ :
$-3(x-4)^{2}+75=0$
$\Rightarrow -3(x-4)^{2}=-75$
$\Rightarrow (x-4)^{2}=25$
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$\Rightarrow x=9, -1$

So the x-intercepts are 9 and -1.

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