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laiz [17]
3 years ago
15

Quick pls!!

Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

Option B

Step-by-step explanation:

The Triangle given is ΔABC.

It is reflected over l mirror so it will form a image like ΔQRS.

Again the triangle is reflected over mirror m so it will form a image like ΔXYZ.

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Which inequality is used to find the domain<br>​
Igoryamba
<h3>Answer: Choice D.  5x-5 \ge 0</h3>

This is because we want to avoid having negative numbers under the square root. So we make the radicand to be 0 or larger.

The +1 at the end doesn't affect the domain.

4 0
3 years ago
Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa
zimovet [89]

Answer:

x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

Step-by-step explanation:

We are given that a quadratic equation

x^2-x-1=0

We have to solve the equation by completing square and find the value of b.

(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0

(x-\frac{1}{2})^2-\frac{1}{4}-1=0

(x-\frac{1}{2})^2-\frac{1-4}{4}=0

(x-\frac{1}{2})-\frac{5}{4}=0

(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0

(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2

x-\frac{1}{2}=\frac{\sqrt5}{2} and x-\frac{1}{2}=-\frac{\sqrt5}{2}

x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}

And x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}

Therefore,x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

6 0
3 years ago
Graph the function.<br> f(x)=2x^2-5
LenaWriter [7]

Answer:

x +2xπ5+2f

Step-by-step explanation:

This is the wrong answer lol

4 0
3 years ago
Pls show work, need help
Dahasolnce [82]
You should multiply high and base than divided by 2
Because triangle area formula is this.
5.x^3.y^-1.z times 4.x^5.y^2
---------------------------------------
2
So answer is ; 10.x^8.y^1.z
3 0
3 years ago
Please could someone help me
kow [346]

Answer:

290...................

4 0
3 years ago
Read 2 more answers
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