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3 years ago

Quick pls!!

Mathematics

1 answer:

Gala2k [10]3 years ago

6 0

Answer:

Option B

Step-by-step explanation:

The Triangle given is ΔABC.

It is reflected over l mirror so it will form a image like ΔQRS.

Again the triangle is reflected over mirror m so it will form a image like ΔXYZ.

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Which inequality is used to find the domain<br>

Igoryamba

<h3>Answer: Choice D. $5x-5 \ge 0$ </h3>

This is because we want to avoid having negative numbers under the square root. So we make the radicand to be 0 or larger.

The +1 at the end doesn't affect the domain.

4 0

3 years ago

Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa

zimovet [89]

Answer:

$x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2-x-1=0$

We have to solve the equation by completing square and find the value of b.

$(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0$

$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

$x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}$

And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

Therefore, $x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

6 0

3 years ago

Graph the function.<br> f(x)=2x^2-5

LenaWriter [7]

Answer:

x +2xπ5+2f

Step-by-step explanation:

This is the wrong answer lol

4 0

3 years ago

Pls show work, need help

Dahasolnce [82]

You should multiply high and base than divided by 2
Because triangle area formula is this.
5.x^3.y^-1.z times 4.x^5.y^2
---------------------------------------
2
So answer is ; 10.x^8.y^1.z

3 0

3 years ago

Please could someone help me

kow [346]

Answer:

290...................

4 0

3 years ago

Read 2 more answers